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egoroff_w [7]
4 years ago
9

How many molecules are in 1 mol of the chemical equation shown above

Chemistry
1 answer:
aivan3 [116]4 years ago
7 0
There's 6.022×10^23 particles in 1 mole of anything

like there is 1000 grams in 1 kilogram of anything
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-, or stirring, of the solute in the solvent
Hoochie [10]
Agitation, or stirring of the solute in the solvent increases the solubility of the solution
7 0
3 years ago
Compute the percent ionic character of the interatomic bonds for the following compounds : a. TiO2 b. ZnTe c. CsCld. InSb e. MgC
sesenic [268]

Answer:

a. 63.2%

b. 11.7%

c. 73.3%

d. 0.995%

e. 55.5%

Explanation:

An ionic compound is a compound that is formed by ions, so one of the elements must donate electrons (which is the cation, the positive ion), and the other will receive these electrons (which is the anion, the negative ion).

The power of an element has to attract the electrons is called electronegativity, and so, as higher is the difference of electronegative of the elements, it is more probable that one of them will "still" the electrons and will form an ionic compound. The percent of this ionic character can be found by the Pauling's equation:

%IC = (1 - e^{-0.25*(x_A - x_B)^2}) *100%

Where x_A - x_B is the electronegativity difference of the elements. Thus, consulting an electronegativity table:

a. x_{Ti} = 1.5

x_{O} = 3.5

%IC = (1 - e^{-0.25*(3.5 - 1.5)^2})*100%

%IC = 63.2%

b. x_{Zn} = 1.6

x_{Te} = 2.1

%IC = (1 - e^{-0.25*(2.1 - 1.6)^2})*100%

%IC = 11.7%

c. x_{Cs} = 0.7

x_{Cl} = 3.0

%IC = (1 - e^{-0.25*(3.0 - 0.7)^2})*100%

%IC = 73.3%

d. x_{In} = 1.7

x_{Sb} = 1.9

%IC = (1 - e^{-0.25*(1.9 - 1.7)^2})*100%

%IC = 0.995 %

e. x_{Mg} = 1.2

x_{Cl} = 3.0

%IC = (1 - e^{-0.25*(3.0 - 1.2)^2})*100%

%IC = 55.5%

4 0
3 years ago
On the basis of the diagram, which of the following statements is true?
Furkat [3]
The answer is d I'm pretty sure because the second one and the first one don't make sense but I'm not 100 percent positive about it not being d ..... sorry if it's wrong.
5 0
3 years ago
Read 2 more answers
WILL GIVE BRAINYEST! please help
RoseWind [281]
The answer is c i need brainlyest plz 
5 0
4 years ago
When an ionic compound such as sodium chloride (NaCl) is placed in water, the component atoms of the NaCl crystal dissociate int
sesenic [268]

Answer:

  • <em>The solution expected to contain the greatest number of solute particles is: </em><u>A) 1 L of 1.0 M NaCl</u>

Explanation:

The number of particles is calculated as:

a) <u>For Ionic compounds</u>:

  • molarity × volume in liters × number of ions per unit formula.

b) <u>For covalent compounds</u>:

  • molarity × volume in liters

The difference is a factor which is the number of particles resulting from the dissociation or ionization of one mole of the ionic compound.

So, calling M the molarity, you can write:

  • # of particles = M × liters × factor

This table show the calculations for the four solutions from the list of choices:

Compound    kind         Particles in solution  Molarity   # of particles

                                       (dissociation)              (M)          in 1 liter

A) NaCl          ionic            ions Na⁺ and Cl⁻        1.0            1.0 × 1 × 2 = 2

B) NaCl          ionic            ions Na⁺ anc Cl⁻        0.5           0.5 × 1 × 2 = 1

C) Glucose    covalent     molecules                   0.5          0.5 × 1 × 1 = 0.5

D) Glucose    covalent     molecules                   1.0           1.0 × 1  × 1 = 1

Therefore, the rank in increasing number of particles is for the list of solutions given is: C < B = D < A, which means that the solution expected to contain the greatest number of solute particles is the solution A) 1 L of 1.0 M NaCl.

8 0
3 years ago
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