Answer: This can be quickly solved with "traintracks"
Explanation:
You start w/ grams of water and want to find moles of oxygen gas produced.
So you want to Convert:
Grams of water -> moles of water -> moles of oxygen gas.
The two things you need to know to set up the tracks are:
1)Molar mass of water- H2O
Hydrogen - 1.008(x2)
Oxygen - 16.00
Water - 18.016
If the stigma is messed up it is hard for bees or insects to pollinate because the way they pollinate is by eating the nectar from the stigma and stick the pollen on their body and stick it on the stigma.
But if there is no stigma=no pollination
A good example of a model is a lily
Answer:
1.4 × 10^-4.
Explanation:
C3H6O3 + H2O <======> C3H5O3^- + H3O^+ ------------------------------------------(1).
So, from the question above we are given the following parameters or data which is going to help in solving this particular Question/problem;
=>concentration of the solution of lactic acid (CH3CH(OH)C00H) = 0.1 M and pH = 2.44.
Therefore, the concentration of the hydrogen ion[H^+} can be determined from the pH formula given below;
pH = - log { H^+}.
2.44 = - log { H^+}.
Therefore, {H^+} = 0.0036 M.
From the equation (1) given above, we have that the ratio for the equilibrium reaction is 1 : 1 : 1 :1. Therefore, molarity of C3H5O3^- = 0.0036 M and the molarity of C3H6O3 =( 0.1 - 0.0036 M) = 0.0964 M at equilibrium.
Hence, ka = {C3H5O3^-} { H3O^+} /{C3H6O3} = ( 0.0036 M)^2 /(0.0964 M) = 1.4 × 10^-4.
The answer is 14.8 hoped this helped
