Answer:
8 mins and 20 seconds i think
Explanation:
Solubility of barium chloride at 30 degree Celsius is 38.2g /100 g water and solubility of barium chloride at 60 degree Celsius is 46.6 g / 100 g water.
The quantity of barium chloride that is dissolved in water at 30 degree Celsius = 38.2 * [150/100] = 57.30 g.
The quantity of barium chloride that will be dissolved in water at 60 degree Celsius = 46.6 * [150/100] = 69.90 g
The difference between these quantities is the amount of barium chloride that can be dissolved by heating the barium chloride to 60 degree Celsius.
69.90 - 57.30 = 12.60 g. Therefore, 12.60 g of barium chloride can still be dissolved in the water by heating the water to 60 degree Celsius.
Answer:
Oxidative phosphorylation proceeds with the formation of energy laden molecules i.e; carbondioxide and water.
Therefore, Total CO₂ production is directly related to VCO₂ = R x VO₂
where, R is the respiratory quotient varing among 0.7 to 1.0 according to the energy intake (ATP) ie 0.25 of the total diet consumed .
VO₂ is, as mentioned above arterial venous oxygen difference = 6.2ml/dl
therefore, VCO₂ = 0.25 x 6.2
= 1.55 ml/dl
ie; VO₂ : VCO₂ = 6.2 : 1.55.
Explanation:
Isotopes are atoms of the same element that<span> has different masses.</span>
Answer:
Explanation:
We will need a balanced chemical equation with masses, moles, and molar masses.
1. Gather all the information in one place:
Mᵣ: 18.02
2Na + H₂O ⟶ 2NaOH + H₂
m/g: 72.0
2. Moles of H₂O
3. Moles of Na
The molar ratio is 2 mol Na/1 mol H₂O.
