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Kruka [31]
3 years ago
9

Please help ASAP! Which expression is equal to the number of kilograms (kg) in 3700 milligrams

Chemistry
1 answer:
aev [14]3 years ago
6 0

Answer is C my g. Don't really know how to explain it.

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In the reaction of sodium and oxygen, which atom is the reducing agent?
pishuonlain [190]
Sodium is the reducing agent because a reducing agent is always the donor of electrons.
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2 years ago
A sealed 10.0 L flask at 400 K contains equimolar amounts of ethane and propanol in gaseous form. Which of the following stateme
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Answer:

(C) The average molecular speed of ethane is equal to the average molecular speed of propanol.

Explanation:

When dealing with gases, you know that the temperature and speed are related. When held at a constant temperature, the speed is also held constant. We also know that ideal gases behave the same despite their identities.

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2 years ago
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When the pH of a solution changes from a pH of 5 to a pH of 3, the hydronium ion concentration is
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Answer : The correct option is, (D) 100 times the original content.

Explanation :

As we are given the pH of the solution change. Now we have to calculate the ratio of the hydronium ion concentration at pH = 5 and pH = 3

As we know that,

pH=-\log [H_3O^+]

The hydronium ion concentration at pH = 5.

5=-\log [H_3O^+]

[H_3O^+]=1\times 10^{-5}M      ..............(1)

The hydronium ion concentration at pH = 3.

3=-\log [H_3O^+]

[H_3O^+]=1\times 10^{-3}M      ................(2)

By dividing the equation 1 and 2 we get the ratio of the hydronium ion concentration.

\frac{[H_3O^+]_{original}}{[H_3O^+]_{final}}=\frac{1\times 10^{-5}}{1\times 10^{-3}}=\frac{1}{100}

100\times [H_3O^+]_{original}=[H_3O^+]_{final}

From this we conclude that when the pH of a solution changes from a pH of 5 to a pH of 3, the hydronium ion concentration is 100 times the original content.

Hence, the correct option is, (D) 100 times the original content.

7 0
3 years ago
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What atom has 35 protons and 47 neutrons ?
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Answer:

Bromine

Explanation:

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2 years ago
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What is the molarity of a solution prepared by diluting 43.72 ml of 1.005 M aqueous K2CR2O7 to 500 ml
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Answer:

43.72

Explanation:

that is the answer hope u liked it and I did this already along time ago

3 0
3 years ago
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