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Kruka [31]
3 years ago
9

Please help ASAP! Which expression is equal to the number of kilograms (kg) in 3700 milligrams

Chemistry
1 answer:
aev [14]3 years ago
6 0

Answer is C my g. Don't really know how to explain it.

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liberstina [14]
<span>I believe its, the federal principle or system of government. Hope this can help!! >-<</span>
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3 years ago
What is mg is it length, area, volume, mass, density, time or tenperature
Akimi4 [234]
Mg stands for Milligram
8 0
3 years ago
5. Name five plants and animals that lived in ancient Antarctica
Andrew [12]

Answer:

Two hundred million years ago, Antarctica was a lush, temperate rainforest home to crocodile-sized amphibians and rhinoceros-sized dinosaurs.

Explanation:

Animals:

1 ankylosaurs (the armored dinosaurs), mosasaurs and plesiosaurs (both marine reptilian groups).

2 Cry-oloph-os-auru-s was the ap-ex pre-da-tor of its region when it hunted in the lands of Jur-as-sic Period Antarctica.

3 plesiosaurs.

4 mosasaurs.

Plants:

1 palm trees.

2 ferns and Tanglefoot.

3 Evergreen trees

4 Glossopteris

8 0
2 years ago
Hydrogen sulfide,H2S, is a very toxic gas with a smell of rotten eggs. using the following: H2S+3/2 O2=SO2+H2O H2+1/2O2=H2O S+O2
Serga [27]

Answer:

ΔH = -20kJ

Explanation:

The enthalpy of formation of a compound is defined as the change of enthalpy during the formation of 1 mole of the substance from its constituent elements. For H₂S(g) the reaction that describes this process is:

H₂(g) + S(g) → H₂S(g)

Using Hess's law, it is possible to sum the enthalpies of several reactions to obtain the change in enthalpy of a particular reaction thus:

<em>(1) </em>H₂S(g) + ³/₂O₂(g) → SO₂(g) + H₂O(g) ΔH = -519 kJ

<em>(2) </em>H₂(g) + ¹/₂O₂(g) → H₂O(g) ΔH = -242 kJ

<em>(3) </em>S(g) + O₂(g) → SO₂(g) ΔH = -297 kJ

The sum of -(1) + (2) + (3) gives:

<em>-(1) </em>SO₂(g) + H₂O(g) → H₂S(g) + ³/₂O₂(g) ΔH = +519 kJ

<em>(2) </em>H₂(g) + ¹/₂O₂(g) → H₂O(g) ΔH = -242 kJ

<em>(3) </em>S(g) + O₂(g) → SO₂(g) ΔH = -297 kJ

<em>-(1) + (2) + (3): </em><em>H₂(g) + S(g) → H₂S(g) </em>

<em>ΔH =</em> +519kJ - 242kJ - 297kJ = <em>-20 kJ</em>

<em />

I hope it helps!

5 0
3 years ago
Write the condensed ground-state electron configurations of these transition metal ions, and state which are paramagnetic:
jok3333 [9.3K]

Answer:

a) Mo the electron configuration: 42Mo: 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d4

Mo3+ - is Paramagnetic

b) Au - [Xe] 4f14 5d10 6s1

For Au+ is not paramagnetic

c) Mn - [Ar] 3d5 4s2

Mn2+ is paramagnetic

d)Hf -[Xe] 4f¹⁴ 5d² 6s²

Hf2+ is not paramagnetic

Explanation:

An atom becomes positively charged when it looses an electron.

Diamagnetism in atom occurs whenever two electrons in an orbital paired equalises with a total spin of 0.

Paramagnetism in atom occurs whenever at least one orbital of an atom has a net spin of electron. That is a paramagnetic electron is just an unpaired electron in the atom.

Here is a twist even if an atom have ten diamagnetic electrons, the presence of at least one paramagnetic electron, makes it to be considered as a paramagnetic atom.

Simply put paramagnetic elements are one that have unpaired electrons, whereas diamagnetic elements do have paired electron.

3 0
3 years ago
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