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Kruka [31]
3 years ago
9

Please help ASAP! Which expression is equal to the number of kilograms (kg) in 3700 milligrams

Chemistry
1 answer:
aev [14]3 years ago
6 0

Answer is C my g. Don't really know how to explain it.

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What would be the mass of a 33.5dm3 sample of O2 at STP?
liraira [26]

Answer:

• One mole of oxygen is equivalent to 16 grams.

→ But at STP, 22.4 dm³ are occupied by 1 mole.

{ \tt{22.4 \:  {dm}^{3}   \: \dashrightarrow \: 16 \: grams}} \\  { \tt{33.5 \:  {dm}^{3}  \:  \dashrightarrow \: ( \frac{33.5 \times 16}{22.4} ) \: grams}} \\  \\  \dashrightarrow \: { \boxed{ \tt{23.94 \: g \approx \: 24 \: grams}}}

7 0
2 years ago
You have a saturated solution of BaSO4, a slightly soluble ionic compound. What happens if you add Ba(OH)2, NaNO3, and CuSO4 to
igomit [66]

Answer:

- Addition of Ba(OH)2: favors the formation of a precipitate.

- Undergo a chemical reaction forming soluble species.

- Addition of CuSO4 : favors the formation of a precipitate.

Explanation:

Hello,

In this case, since the dissociation reaction of barium sulfate is:

BaSO_4(s)\rightleftharpoons Ba^{2+}(aq)+SO_4^{2-}(aq)

We must analyze the effect of the common ion:

- By adding barium hydroxide, more barium ions will be added to the equilibrium system so the formation of solid barium sulfate will be favored (reaction shifts leftwards towards reactants).

- By adding sodium nitrate, the following reaction will undergo:

BaSO_4(s)+NaNO_3(aq)\rightarrow Ba(NO_3)_2(aq)+Na_2SO_4(aq)

So the precipitate will turn into other soluble species.

- By adding copper (II) sulfate, more sulfate ions will be added to the equilibrium system so the formation of solid barium sulfate will be favored (reaction shifts leftwards towards reactants).

All of this is supported by the Le Chatelier's principle.

Best regards.

7 0
2 years ago
_____ C8H8 + _____ O2 _____ CO2 + _____ H2O
Effectus [21]

What do you want for the answer the balance equation?

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3 years ago
A learner was assigning oxidation numbers for different elements in the compounds OF2 and NaF. The learner assigned F an oxidati
77julia77 [94]

Answer: B. No, fluorine is always assigned an oxidation number of -1.

Explanation:

6 0
2 years ago
HELPPPP. SHOW WORK
nekit [7.7K]
I think The answer to two is it would sink
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3 years ago
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