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kap26 [50]
3 years ago
10

If 0.45 mols of MnO2 can react with 0.28 moles of HCl, how many moles of Cl2 could be produced

Chemistry
1 answer:
Archy [21]3 years ago
3 0
MnO₂ + 4HCl = MnCl₂ + 2H₂O + Cl₂

n(MnO₂)=0.45 mols
n(HCl)=0.28 mols

0.45 : 0.28 = 1 : 0.622
the reaction equation   1:4
the hydrogen chloride in the lack

n(Cl₂)=n(HCl)/4
n(Cl₂)=0.28/4=0.07 mols
formed 0.07 mols of chlorine
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Since atoms have more than one electron (other than atomic hydrogen) how do you account for the electrons remaining associated w
WARRIOR [948]
Answer: the electrons remain around the atomic nuclei due to the existence of a positive charge on the nuclei that, of course, atract the negative charged electrons. The protons are the paricles in the nuclei that hold the positive charge.

Justification:

First, I wish to explaing the sense of the question. The question arises because given that the electrons have negative electric charge how is that they do not repeal each other to the point that they end leaving the nucleous of the atom alone.

This is you know that equal charges repel each other, so how is it that the electrons stand around the nucleous instead of separateing and levaing the atomic nucleous alone.

The answer is due to the existence of a positive charge on the nuclei that, of course, atract the negative charged electrons. That positive charge is the protons.

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8 0
3 years ago
The concentration of a saturated BaCl2 solution is 1.75 M (mol/liter) and the concentration of a saturated Na2SO4 solution is 2.
Kitty [74]

Answer:

a) The theoretical yield is 408.45g of BaSO_{4}

b) Percent yield = \frac{realyield}{408.45g}*100

Explanation:

1. First determine the numer of moles of BaCl_{2} and Na_{2}SO_{4}.

Molarity is expressed as:

M=\frac{molessolute}{Lsolution}

- For the BaCl_{2}

M=\frac{1.75molesBaCl_{2}}{1Lsolution}

Therefore there are 1.75 moles of BaCl_{2}

- For the Na_{2}SO_{4}

M=\frac{2.0moles[tex]Na_{2}SO_{4}}{1Lsolution}[/tex]

Therefore there are 2.0 moles of Na_{2}SO_{4}

2. Write the balanced chemical equation for the synthesis of the barium white pigment, BaSO_{4}:

BaCl_{2}+Na_{2}SO_{4}=BaSO_{4}+2NaCl

3. Determine the limiting reagent.

To determine the limiting reagent divide the number of moles by the stoichiometric coefficient of each compound:

- For the BaCl_{2}:

\frac{1.75}{1}=1.75

- For the Na_{2}SO_{4}:

\frac{2.0}{1}=2.0

As the BaCl_{2} is the smalles quantity, this is the limiting reagent.

4. Calculate the mass in grams of the barium white pigment produced from the limiting reagent.

1.75molesBaCl_{2}*\frac{1molBaSO_{4}}{1molBaCl_{2}}*\frac{233.4gBaSO_{4}}{1molBaSO_{4}}=408.45gBaSO_{4}

5. The percent yield for your synthesis of the barium white pigment will be calculated using the following equation:

Percent yield = \frac{realyield}{theoreticalyield}*100

Percent yield = \frac{realyield}{408.45g}*100

The real yield is the quantity of barium white pigment you obtained in the laboratory.

7 0
3 years ago
In order for matter or energy to be conserved, one must have a ____ system.
Leya [2.2K]
Closed system.  If the system is not closed, matter or energy can escape from the system.  an example of this is if you react magnesium and hydrochloric acid in a open system.  The H₂ gas is going to escape making it look like some of the mass disappeared .  in that same reaction some in an open system will also loose heat to the surrounding which will make it look like less heat was produced.
6 0
3 years ago
Read 2 more answers
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Answer:

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Explanation:

Given data:

pH of solution = 4.5

Hydrogen ion concentration = ?

Solution;

pH = -log [H⁺]

we will rearrange this formula:

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[H⁺] = 10⁻⁴°⁵

[H⁺] =  3.16 × 10⁻⁵ mol/L

4 0
3 years ago
What happens to the temperatures when we have direct sunlight vs indirect sunlight?
lawyer [7]

Explanation:

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