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Rainbow [258]
3 years ago
5

A small cube of iron and a large flat sheet of iron contain the same volume. Which one will completely rust first? Explain why.

Chemistry
2 answers:
Y_Kistochka [10]3 years ago
8 0

Answer:

The flat sheet will completely rust before the iron cube. Since they both have the same volume, the flat sheet has more surface area than the small cube. This means more particles are exposed on the flat sheet that can react in a chemical reaction.

Hunter-Best [27]3 years ago
4 0

The flat sheet will completely rust before the iron cube. Since they both have the same volume, the flat sheet has more surface area than the small cube. This means more particles are exposed on the flat sheet that can react in a chemical reaction.

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Describe what happens as ice changes to water.
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Ancient Romans built often out of bricks and mortar. A key ingredient in their mortar was quicklime (calcium oxide), which they
velikii [3]

The question has missing information. At part 1 it is "Write a balanced chemical equation, including physical state symbols, for the decomposition of solid calcium carbonate (CaCO3) into solid calcium oxide and gaseous carbon dioxide."

Part 2. "Suppose 19.0 L of carbon dioxide gas are produced by this reaction, at a temperature of 290.0°C and pressure of exactly 1 atm. Calculate the mass of calcium carbonate that must have reacted (...)"

Answer:

41.0 g

Explanation:

1. Calcium oxide has molecular formula CaO and carbon dioxide CO₂, thus, the reaction will be:

CaCO₃(s) → CaO(s) + CO₂(g)

The equation is already balanced because there's the same number of each element on both sides.

2. First, let's calculate the number of moles of CO₂ produced by the ideal gas law:

PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant (0.082 atm.L/mol.K), and T is the temperature (290°C = 273 = 563 K).

1*19 = n*0.082*563

46.166n = 19

n = 0.4116 mol

By the stoichiometry of the reaction:

1 mol of CaCO₃ ------ 1 mol of CO₂

x ----- 0.4116 mol

By a simple direct three rule:

x = 0.4116 mol of CaCO₃.

The molar mass of the calcium carbonate is 100 g/mol, thus the mass (m) is the number of moles multiplied by it:

m = 0.4116*100

m = 41.16 g = 41.0 g

4 0
3 years ago
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