Answer:
2954.6 N/C, 46.36 degree from positive axis
Explanation:
E1 = 1300 N/C, θ1 = 35 degree
E2 = 1700 N/C, θ2 = 55 degree
Now write the electric fields in vector form
E1 = 1300 ( Cos 35 i + Sin 35 j) = 1064.9 i + 745.6 j
E2 = 1700 ( Cos 55 i + Sin 55 j) = 975.08 i + 1392.6 j
Resultant electric field
E = E1 + E2
E = 1064.9 i + 745.6 j + 975.08 i + 1392.6 j
E = 2039.08 i + 2138.2 j
Magnitude of E
E = sqrt (2039.08^2 + 2138.2^2)
E = 2954.6 N/C
Let it makes an angle Φ from X axis
tan Φ = 2138.2 / 2039.08 = 1.049
Φ = 46.36 degree from positive X axis.
First of all the kinetic energy is when the particles move in continuous random motion.
If the temperature is high the colliding particles will collide more. and if the temperature is low the colliding particles will collide less.
Low temperature result in low kinetic energy
High temperature result in high kinetic energy
Absolute zero is the point where where all molecules have no kinetic energy. It is a theoretical value (it has never been reached).
The Kelvin temperature scale is based on absolute zero being the lowest possible temperature that could theoretically be reached. That is why there is no such thing as a negative Kelvin temperature value.
A :-) for this question , we should apply
a = v - u by t
Given - u = 4.77 m/s
v = 23.5 m/s
t = 5.18 m/s
Solution -
a = v - u by t
a = 23.5 - 4.77
a = 28.27 m/s^2
.:. The acceleration is 28.27 m/s^2
Answer:
The second dart leaves the gun two times as faster than the first one.
Explanation:
Assuming no energy loss during the spring-dart energy transfer, we have by the conservation of energy principle

Given an arbitrary
and its double,
, launch velocities are
