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Papessa [141]
4 years ago
6

Parasaurolophus was a dinosaur whose distinguishing feature was a hollow crest on the head. The 1.5-m-long hollow tube in the cr

est had connections to the nose and throat, leading some investigators to hypothesize that the tube was a resonant chamber for vocalization. If you model the tube as an open-closed system, what are the first three resonant frequencies? Assume a speed of sound of 350 m/s.
Physics
1 answer:
Inessa05 [86]4 years ago
8 0

Answer:

58.33 Hz

175 Hz

291.67 Hz

Explanation:

L = Length of tube = 1.5 m

v = Speed of sound in air = 350 m/s

The first resonant frequency is given by

f_1=\dfrac{v}{4L}\\\Rightarrow f_1=\dfrac{350}{4\times 1.5}\\\Rightarrow f_1=58.33\ Hz

The first resonant frequency is 58.33 Hz

The second resonant frequency is given by

f_2=3\dfrac{v}{4L}\\\Rightarrow f_2=3\dfrac{350}{4\times 1.5}\\\Rightarrow f_2=175\ Hz

The first resonant frequency is 175 Hz

The third resonant frequency is given by

f_3=5\dfrac{v}{4L}\\\Rightarrow f_3=5\dfrac{350}{4\times 1.5}\\\Rightarrow f_3=291.67\ Hz

The first resonant frequency is 291.67 Hz

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Answer:

Crumple zones are designed to absorb and redistribute the force of a collision. ... Also known as a crush zone, crumple zones are areas of a vehicle that are designed to deform and crumple in a collision. This absorbs some of the energy of the impact, preventing it from being transmitted to the occupants.

4 0
3 years ago
The Moon's center is 3.9x10 m from Earth's center. The Moon is 1.5x10^8 km from the Sun's center. If the mass of the Moon is 7.3
nika2105 [10]

Explanation:

It is given that The Moon's center is 3.9x10⁸ m from Earth's center. The moon 1.5x10⁸ km from the Sun's center. We need to find the ratio of the gravitational forces exerted by Earth and the Sun on the Moon.

The gravitational force is given by :

F=\dfrac{Gm_em_m}{r^2}

It means F\propto \dfrac{1}{r^2}

So,

\dfrac{F_1}{F_2}=\dfrac{r_2}{r_1}

r₁ = 3.9x10⁸ km

r₂= 1.5x10⁸ km

So,

\dfrac{F_1}{F_2}=\dfrac{1.5\times 10^8}{3.9\times 10^8}\\\\\dfrac{F_1}{F_2}=\dfrac{5}{13}

Hence, the ratio of the gravitational forces exerted by Earth and the Sun on the Moon is 5:13.

3 0
4 years ago
Multiply 5.036×102m by 0.078×10−1, taking into account significant figures.
Anika [276]

Answer : The significant digit is 6

Explanation :

Multiply 5.036\times10^{2}m by 0.078\times10^{-1}m

Now, on multiplying

5.036\times10^{2}m \times0.078\times10^{-1}m = 0.392808 \times10^{1}\ m^{2}

5.036\times10^{2}m \times0.078\times10^{-1}m = 0.0392808\ m^{2}

Now, the significant digit is 6.

Hence, this is the required solution.

3 0
3 years ago
A ball is thrown vertically downward from the top of a 30.6-m-tall building. The ball passes the top of a window that is 10.7 m
Gekata [30.6K]

Answer:

v = 19.6 m/s

Explanation:

Height of building = 30.6 m.

Height of window from the ground level= 10.7 m.

Acceleration due to gravity = 9.8 \frac{m}{s^2}

At initial condition ball at rest condition so u= 0 m/s.

Lets take when passes through the window ,velocity is v.

Here acceleration is constant so we can apply motion equation .

We know that

v= u + a t

So by putting the values

v = 0 +9.8 x 2

v = 19.6 m/s

So the velocity of ball is 19.6 m/s when passes through the window after 2 s.

7 0
4 years ago
Is the cell membrane found in Plant Cell, Animal Cell, or Both?
Brut [27]

Answer:

Explanation:

Animal cells and plant cells share the common components of a nucleus, cytoplasm, mitochondria and a cell membrane. Plant cells have three extra components, a vacuole, chloroplast and a cell wall.

7 0
3 years ago
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