Answer:
6.32 moles of Fe
Explanation:
The given chemical equation is presented as follows;
2Fe + 3Cl₂ → 2FeCl₃
The mass of Cl₂ in the reaction = 336 grams
The molar mass of chlorine gas Cl₂ = 35.435 g/mol
The number of moles, n = Mass/(Molar mass)
The number of moles of Cl₂ in the reaction, n = 336 g/(35.435 g/mol) ≈ 9.842 moles
From the given reaction, 3 moles of Cl₂ react with 2 moles of Fe to produce 2 moles of FeCl₃
By the law of definite proportions, we have that 9.482 moles of Cl₂ will react with approximately 9.482 × 2/3 = 6.32 moles of Fe to produce approximately 6.32 moles of FeCl₃
Therefore, approximately 6.32 moles of Fe will be required to react with 336 grams of Cl₂.
