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4 years ago

6

When converting an “ordinary” number that is greater than 1 to scientific notation, how many non-zero digits are to the LEFT of

the decimal point when you are finished?

1 answer:

oksian1 [2.3K]4 years ago

5 0

Answer: 0 I think

Explanation:

pretty sure its zero because i learned it last year but im in middle school so you might want to look it up.

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For salt formation procedure crude lidocaine should be dissolved in diethyl ether and 2 ml of 2.2 M sulfuric acid should be adde

mixas84 [53]

Answer:

20 equivalents of sulfuric acid are needed to per equivalent of lidocaine.

Explanation:

To do this calculation we should take in account the key information given:

<em>2 mL (0.02 L) of sulfuric acid (H2SO4) 2.2 M per 1 g of lidocaine (molecular weight=234.34 g/mol)</em>

So we can calculate from here the number of moles of each compound needed for the procedure.

Starting with the sulfuric acid, we know that the molar concentration is defined as [concentration] =n(moles number)/V(volume).

So n=[concentration]*V, and therefore :

n(H2SO4)=2.2 M * 0.02 L=0.044 mol

While the moles of lidocaine can be calculated as n(moles number)=m(mass amount)/mW(molecular weight), so:

n(lidocaine)=m(lidocaine)/mW(lidocaine)= 1 g /234,34 g/mol~0,0043 mol.

Now we can calculate the equivalents.

Take in account that for sulfuric acid, de number of equivalents per mole is 2 (because of the double dissociation of the acid), while the number of equivalents per mole of lidocaine is 1.

Then we can conclude that:

0,0043 equivalents of lidocaine need 0,088 equivalents of sulfuric acid

1 equivalent of lidocaine need (0,088/0.0043)=20,46~20 equivalents of sulfuric acid

Finally, we can conclude that for the described procedure, 20 equivalents of sulfuric acid per equivalent of lidocaine are needed.

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3 years ago

Design an experiment for molar mass using research skills

nexus9112 [7]

Chemistry is a very hard subject in my opinion

7 0

3 years ago

Plz help me I am timed!!

Aleonysh [2.5K]

Answer:

What do you need help with

Explanation:

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3 years ago

Read 2 more answers

Which shows an isomer of the molecule below?

babunello [35]

Above question is incomplete. Complete question is attached below
.......................................................................................................................

Correct Answer: Option D i.e. CH3CH2CH2CH2CH3

Reason:
Isomers are the compounds having same molecular formula, but different structural formula.

The molecular formula of the compound is C5H12

The compound present is question (i.e. 2-methyl butane) and option D (n-pentane) has same molecular formula. Hence, they are isomers.

However, compound present in option A, is the same compound provided in question. Hence, it is not an isomer. Compounds reported in option B and C has one carbon atom less and more, respectively as compared to the compound reported in question. Hence, they are also not isomers.

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3 years ago

The structure of two compounds are shown: which statement is true?

ankoles [38]

Answer:

Explanation:

The first one. They are both alcohol groups

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3 years ago