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Gelneren [198K]
3 years ago
14

Is a eagle a producer?

Chemistry
1 answer:
Galina-37 [17]3 years ago
4 0
The eagle is not a producer its a consumer
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Is a blood vessel an organ
Alika [10]
Yes, but they are tubular organs and like all other organs are made up of tissues
7 0
3 years ago
Read 2 more answers
if 3.0 grams of aluminum and 6.0 grams of bromine react to form AlBr3, how many grams of product would theoretically be produced
Gelneren [198K]
1) Chemical reaction: 2Al + 3Br₂ → 2AlBr₃.
m(Al) = 3,0 g.
m(Br₂) = 6,0 g.
n(Al) = m(Al) ÷ M(Al).
n(Al) = 3,0 g ÷ 27 g/mol.
n(Al) = 0,11 mol.
n(Br₂) = n(Br₂) ÷ m(Br₂).
n(Br₂) = 6 g ÷ 160 g/mol.
n(Br₂) = 0,0375 mol; limiting reagens.
n(Br₂) : n(AlBr₃) = 3 : 2.
n(AlBr₃) = 0,025 mol.
m(AlBr₃) = 0,025 mol · 266,7 g/mol.
m(AlBr₃) = 6,67 g.

2) m(Br₂) - all bromine reacts, so mass of bromine after reaction is zero grams (m(Br₂) = 0 g).
n(Al) = 0,11 mol - 0,025 mol = 0,085 mol.
m(Al) = 0,085 mol · 27 g/mol.
m(Al) = 2,295 g.
m(AlBr₃) = 6,67 g · 0,72 (yield of reaction).
m(AlBr₃) = 4,8 g.
n - amount of substance.
M - molar mass.

4 0
3 years ago
What is colligative property? why does theproperty changes the way that it does when the amount of solute is increased. State an
elena-14-01-66 [18.8K]

Colligative properties are those substances that depend on the number of substances in the solution, not in the identity of that substance. The property changes the way that it does when the amount of solute is increased because it enables the solute to be scattered more. For example, the freezing point of salt water is lower than that of the pure water due to the salt ions present in water.

6 0
3 years ago
Consider the reaction: A (aq) ⇌ B (aq) at 253 K where the initial concentration of A = 1.00 M and the initial concentration of B
Ugo [173]

Answer:

The maximum amount of work that can be done by this system is -2.71 kJ/mol

Explanation:

Maximum amount of work denoted change in gibbs free energy (\Delta G) during the reaction.

Equilibrium concentration of B = 0.357 M

So equilibrium concentration of A = (1-0.357) M = 0.643 M

So equilibrium constant at 253 K, K_{eq}= \frac{[B]}{[A]}

[A] and [B] represent equilibrium concentrations

K_{eq}=\frac{0.357}{0.643}=0.555

When concentration of A = 0.867 M then B = (1-0.867) M = 0.133 M

So reaction quotient at this situation, Q=\frac{0.133}{0.867}=0.153

We know,  \Delta G=RTln(\frac{Q}{K_{eq}})

where R is gas constant and T is temperature in kelvin

Here R is 8.314 J/(mol.K), T is 253 K, Q is 0.153 and K_{eq} is 0.555

So, \Delta G=8.314\times 253\times ln(\frac{0.153}{0.555})mol/K

                           = -2710 J/mol

                            = -2.71 kJ/mol

4 0
3 years ago
State the periodic law, and explain its relation to electron configuration. (Use Na and K in your explanation.)
mina [271]

Answer:

Explanation:

The period law state that when elements are listed in order of their atomic numbers, the elements fall into recurring groups, so that there is a recurrence of similar properties at regular intervals.

Na and K in the periodic table fall into the same group, this is because they both have one electrons in their outermost shell.

Na 11 -1s2 2s2 2p6 3s1

K 19 - 1s2 2s2 2p6 3s2 3p6 4s1

They share similar chemical and physical properties. Na and K are very reactive metals, they can loose/donate their outermost electron to non metals in other to attain stable octet state.

The form ionic compound when they react with non metals.

5 0
3 years ago
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