Answer:
D. Propanol
Explanation:
C3H7OH the presence of alcohol functional group makes it propanol
Question is incomplete, complete question is;
A 34.8 mL solution of 
(aq) of an unknown concentration was titrated with 0.15 M of NaOH(aq).
If it takes 20.4 mL of NaOH(aq) to reach the equivalence point of the titration, what is the molarity of 
? For your answer, only type in the numerical value with two significant figures. Do NOT include the unit.
Answer:
0.044 M is the molarity of (aq).
Explanation:
The reaction taking place here is in between acid and base which means that it is a neutralization reaction .
To calculate the concentration of acid, we use the equation given by neutralization reaction:
where,
are the n-factor, molarity and volume of acid which is
are the n-factor, molarity and volume of base which is NaOH.
We are given:
Putting values in above equation, we get:
0.044 M is the molarity of (aq).
Explanation:
the process where the acids and bases neutralize each other to form salt and water is known as neutrilazation
Answer:
C8H8O2
Explanation:
The molecular formula of a compound is simply a multiple of the empirical formula as shown below:
Molecular formula => [C4H4O]n
From the question given, we were told that molar mass of the compound is 136g/mol. This implies that:
[C4H4O]n = 136
Now, let us find the value of n in order to obtain the desired result. This is illustrated below:
[C4H4O]n = 136
[(12x4) + (4x1) + 16]n = 136
[48 + 4 + 16]n = 136
68n = 136
Divide both side by the coefficient of n i.e 68
n = 136/68
n = 2
Therefore the molecular formula is
=> [C4H4O]n
=> [C4H4O]2
=> C8H8O2
D = g / cm³
Density = mass / volume
D = 360 g / 7.5 cm³
D = 48 g/cm³
answer D
hope this helps!
