The temperature in Waterloo was − 5°C at sunrise. By noon the temperature had risen by 12 Celsius degrees. What was the temperat
2 answers:
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9514 1404 393
Answer:
7953.873
Step-by-step explanation:
The first derivative is ...
f'(x) = 4·3x²·e^x +4x³·e^x = e^x(4x³ +12x²)
Then the second derivative is ...
f''(x) = (12x² +24x)e^x +(4x³ +12x²)e^x
f''(x) = e^x(4x³ +24x² +24x)
So, f''(3) = (e^3)(4·27 +24·9 +24·3) = 396e^3 = 7953.87262158
Rounded to thousandths, this is ...
f''(3) = 7953.873
