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prisoha [69]
3 years ago
12

Describe when the formula for simple interest I = prt would be more useful if it were rearranged

Mathematics
1 answer:
Alja [10]3 years ago
4 0
The concept of interest is centralized on the idea that money has a time value. Your $1,000 today would not have the same worth 10 years after. When interest come into play, the value of your money grows with time. There are two types of interest: simple or compounding. Simple interest is based only on the original deposit. Compounding interest is based on the original deposit, add to that the accumulated interest. So, to put simply, simple interest increases by multiplication, while compounding interest increases exponentially.

In the given equation for simple interest, <span>I = prt, i is the amount of interest earned, P is the present worth, r is the interest rate and t is the amount of time. But what we really want to know is the future worth of our money, not the interest earned Therefore, the equation should be F (future worth) in terms of P, i and t. 

Amount of interest earned = Future worth - Present Worth
I = F - P
Substituting this to the given equation and simplifying,
F - P = Prt
F = P + Prt
F = P(1 + rt)</span>
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tangare [24]

Check the picture below.

well, we want only the equation of the diametrical line, now, the diameter can touch the chord at any several angles, as well at a right-angle.

bearing in mind that <u>perpendicular lines have negative reciprocal</u> slopes, hmm let's find firstly the slope of AB, and the negative reciprocal of that will be the slope of the diameter, that is passing through the midpoint of AB.

\bf A(\stackrel{x_1}{1}~,~\stackrel{y_1}{4})\qquad B(\stackrel{x_2}{5}~,~\stackrel{y_2}{1}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{1}-\stackrel{y1}{4}}}{\underset{run} {\underset{x_2}{5}-\underset{x_1}{1}}}\implies \cfrac{-3}{4} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{slope of AB}}{-\cfrac{3}{4}}\qquad \qquad \qquad \stackrel{\textit{\underline{negative reciprocal} and slope of the diameter}}{\cfrac{4}{3}}

so, it passes through the midpoint of AB,

\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ A(\stackrel{x_1}{1}~,~\stackrel{y_1}{4})\qquad B(\stackrel{x_2}{5}~,~\stackrel{y_2}{1}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{5+1}{2}~~,~~\cfrac{1+4}{2} \right)\implies \left(3~~,~~\cfrac{5}{2} \right)

so, we're really looking for the equation of a line whose slope is 4/3 and runs through (3 , 5/2)

\bf (\stackrel{x_1}{3}~,~\stackrel{y_1}{\frac{5}{2}}) \stackrel{slope}{m}\implies \cfrac{4}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{\cfrac{5}{2}}=\stackrel{m}{\cfrac{4}{3}}(x-\stackrel{x_1}{3})\implies y-\cfrac{5}{2}=\cfrac{4}{3}x-4 \\\\\\ y=\cfrac{4}{3}x-4+\cfrac{5}{2}\implies y=\cfrac{4}{3}x-\cfrac{3}{2}

4 0
3 years ago
Where the perimeter of the base is 7.1 cm and the height of the pyramid is 10.8 cm
xz_007 [3.2K]

Answer:

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Step-by-step explanation:

Its is very easy you just add 7.1 to 10.8.

Perimeter you add

Area you multiply

4 0
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