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3 years ago

Please help me what is 1462 ÷ 58 as a mixed number then put it in simplest form

Mathematics

1 answer:

cestrela7 [59]3 years ago

5 0

25.20, that might help you hopefully!

You might be interested in

Find the surface area

ki77a [65]

Step-by-step explanation:

so for this one u do

$15 \times 9 + 9 \times 4 + 15 \times 4$

231 the times it by 2 for the both sides

231×2=462 cm2

hope this make sense :)

7 0

3 years ago

Five over seven plus blank over six equals fifty one over forty two

NISA [10]

Answer:

The blank is 3

Step-by-step explanation:

1 - Give the blank a variable

x = our blank

2 - Write it out

$\frac{5}{7} + \frac{x}{6} = \frac{51}{42}$

3 - Get the denominators equal

$\frac{5}{7}(\frac{6}{6}) +\frac{x}{6}(\frac{7}{7}) = \frac{51}{42} \\\frac{30}{42}+\frac{7x}{42} = \frac{51}{42}$

4 - Simplify

$\frac{30+7x}{42} = \frac{51}{42} \\ \frac{30+7x}{42} = \frac{51}{42}$

5 - Solve for the numerators

30+7x = 51

-30 -30

7x = 21

x = 3

6 0

3 years ago

A diver descended at a constant rate of 16.05 feet every 3 minutes. Which of the following is true?

bekas [8.4K]

Determine the lower limit of the 95% interval for the true mean weight. ... A diver descended at a constant rate of 12.24 feet every 3 minutes. .... weight of 16.05 ounces. at the 5% level of significance can we conclude that ...

5 0

3 years ago

Find all possible values of α+

const2013 [10]

Answer:

$\rm\displaystyle 0,\pm\pi$

Step-by-step explanation:

please note that to find but α+β+γ in other words the sum of α,β and γ not α,β and γ individually so it's not an equation

===========================

we want to find all possible values of α+β+γ when tanα+tanβ+tanγ = tanαtanβtanγ to do so we can use algebra and trigonometric skills first

cancel tanγ from both sides which yields:

$\rm\displaystyle \tan( \alpha ) + \tan( \beta ) = \tan( \alpha ) \tan( \beta ) \tan( \gamma ) - \tan( \gamma )$

factor out tanγ:

$\rm\displaystyle \tan( \alpha ) + \tan( \beta ) = \tan( \gamma ) (\tan( \alpha ) \tan( \beta ) - 1)$

divide both sides by tanαtanβ-1 and that yields:

$\rm\displaystyle \tan( \gamma ) = \frac{ \tan( \alpha ) + \tan( \beta ) }{ \tan( \alpha ) \tan( \beta ) - 1}$

multiply both numerator and denominator by-1 which yields:

$\rm\displaystyle \tan( \gamma ) = - \bigg(\frac{ \tan( \alpha ) + \tan( \beta ) }{ 1 - \tan( \alpha ) \tan( \beta ) } \bigg)$

recall angle sum indentity of tan:

$\rm\displaystyle \tan( \gamma ) = - \tan( \alpha + \beta )$

let α+β be t and transform:

$\rm\displaystyle \tan( \gamma ) = - \tan( t)$

remember that tan(t)=tan(t±kπ) so

$\rm\displaystyle \tan( \gamma ) = -\tan( \alpha +\beta\pm k\pi )$

therefore when k is 1 we obtain:

$\rm\displaystyle \tan( \gamma ) = -\tan( \alpha +\beta\pm \pi )$

remember Opposite Angle identity of tan function i.e -tan(x)=tan(-x) thus

$\rm\displaystyle \tan( \gamma ) = \tan( -\alpha -\beta\pm \pi )$

recall that if we have common trigonometric function in both sides then the angle must equal which yields:

$\rm\displaystyle \gamma = - \alpha - \beta \pm \pi$

isolate -α-β to left hand side and change its sign:

$\rm\displaystyle \alpha + \beta + \gamma = \boxed{ \pm \pi }$

when is 0:

$\rm\displaystyle \tan( \gamma ) = -\tan( \alpha +\beta \pm 0 )$

likewise by Opposite Angle Identity we obtain:

$\rm\displaystyle \tan( \gamma ) = \tan( -\alpha -\beta\pm 0 )$

recall that if we have common trigonometric function in both sides then the angle must equal therefore:

$\rm\displaystyle \gamma = - \alpha - \beta \pm 0$

isolate -α-β to left hand side and change its sign:

$\rm\displaystyle \alpha + \beta + \gamma = \boxed{ 0 }$

and we're done!

8 0

3 years ago

Read 2 more answers

Which of the following shows the correct steps to find the value of 16^1/4

Scorpion4ik [409]

The answer is B, I hope this helps! (don't forget to give brainliest)

4 0

3 years ago