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Kruka [31]
3 years ago
13

A wheel in this scale drawing is 4 cm wide. The ratio of the drawing is 1:14. How wide is the actual wheel in cm?

Mathematics
1 answer:
bagirrra123 [75]3 years ago
7 0

1:14 means that for every 1 cm it is drawn at it is actually 14 cm

 so multiply 4 x 14 = 56

 it is actually 56 cm wide

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Angles α and β are the two acute angles in a right triangle, where α = 5x 3 + 20 and β = 2x 3 + 14. Find α.
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The acute angles of a right triangle are complementary, so
  α + β = 90
  (5x/3 +20) + (2x/3) + 14) = 90 . . . . . . substitute given values
  7x/3 +34 = 90 . . . . . . . . . . . . . . . . . . . collect terms
  7x/3 = 56 . . . . . . . . . . . . . . . . . . . . . . . subtract 34
  x = (3/7)*56 = 24 . . . . . . . . . . . . . . . . . multiply by 3/7

Then the value of α is ...
  α = 5*24/3 +20 = 60
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Evaluate P(3, 0).<br> 0<br> 1<br> 6
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The graph of f(x) = 2x^2 + 20x + 48 is shown
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Answer:

a) The equation in intercept form by factoring is (x+6)(x+4)

b) From the given graph x- intercepts are (-4,0) and (-6,0) and zeros (roots) of the function are -6 and -4.

c) The solutions of  2x^2+20x+48=0 is (x+6)(x+4)=0 that is x= -6 and x = -4.

Step-by-step explanation:

The given quadratic  equation is f(x)=2x^2+20x+48

Put the function f(x) = 0 , then f(x)=2x^2+20x+48=0

a) The equation in intercept form by factoring is ,

Consider the given function,

f(x)=2x^2+20x+48=0

\Rightarrow 2x^2+20x+48=0

taking 2 common, we get,

\Rightarrow 2(x^2+10x+24)=0

\Rightarrow x^2+10x+24=0

The above is a quadratic equation of the form ax^2+bx+c=0

Solving quadratic equation using middle term splitting method,

\Rightarrow x^2+6x+4x+24=0

\Rightarrow x(x+6)+4(x+6)=0

\Rightarrow (x+6)(x+4)=0

Thus, The equation in intercept form by factoring is (x+6)(x+4).

b) From the given graph x- intercepts are (-4,0) and (-6,0) .

Zeroes / roots of a function are those points where the value of the function is zero.

Put f(x) = 0  as solved above

that is (x+6)(x+4)=0

\Rightarrow (x+6)=0 or \Rightarrow (x+4)=0

\Rightarrow x=-6 or \Rightarrow x=-4

Thus, zeros (roots) of the function are -6 and -4.

For checking put x = -6 and -4 in the function we get f(x) =0 .

c) The solutions of  2x^2+20x+48=0 is (x+6)(x+4)=0 that is x= -6 and x = -4 as shown above.


8 0
3 years ago
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