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3 years ago

What charge will an ion of phosphorus form?

Chemistry

2 answers:

Fed [463]3 years ago

8 0

Answer:

A charge of -3

Explanation:

If you look on a periodic table you will find that phosphorus is 3 elements away from the nearest noble gas argon. This means that phosphorus would prefer a charge of -3!

Ludmilka [50]3 years ago

3 0

Answer:typically it will be -3

Explanation:

It prefers to take up 3 electrons and thereby become phosphide with a -3 charge. since it is a nonmetal it will take up electrons making it negative as an ion. In order to fill up its last shell, to become stable, to form an octet it will need 3 added electrons which will give it that -3 charge. An atom of phophorus will be neutral, An ion of phsphorus will have a -3 charge.

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2 years ago

Which of these events would occur last in a food chain?

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3 years ago

If 27.3% of a sample of silver-112 decays in 1.52 hours, what is the half-life (in hours to 3 decimal places)?

ICE Princess25 [194]

<u>Answer:</u> The half life of the sample of silver-112 is 3.303 hours.

<u>Explanation:</u>

All radioactive decay processes undergoes first order reaction.

To calculate the rate constant for first order reaction, we use the integrated rate law equation for first order, which is:

$k=\frac{2.303}{t}\log \frac{[A_o]}{[A]}$

where,

k = rate constant = ?

t = time taken = 1.52 hrs

$[A_o]$ = Initial concentration of reactant = 100 g

[A] = Concentration of reactant left after time 't' = [100 - 27.3] = 72.7 g

Putting values in above equation, we get:

$k=\frac{2.303}{1.52hrs}\log \frac{100}{72.7}\\\\k= 0.2098hr^{-1}$

To calculate the half life period of first order reaction, we use the equation:

$t_{1/2}=\frac{0.693}{k}$

where,

$t_{1/2}$ = half life period of first order reaction = ?

k = rate constant = $0.2098hr^{-1}$

Putting values in above equation, we get:

$t_{1/2}=\frac{0.693}{0.2098hr^{-1}}\\\\t_{1/2}=3.303hrs$

Hence, the half life of the sample of silver-112 is 3.303 hours.

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4 years ago

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Misha Larkins [42]

Answer:

Explanation:

i hope it helps ;)

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3 years ago