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Cloud [144]
3 years ago
9

Houses with carpet are much quieter than houses with tile or hardwood floors because of sound wave A) absorption. B) diffraction

. C) reflection. Eliminate D) refraction.
Physics
2 answers:
fgiga [73]3 years ago
6 0
<span><u>Answer </u>
A). Absorption

<u>Explanation </u>
Sound travels inform of waves. Waves have certain properties. They can be reflected, diffracted refracted, they can also be absorbed. Some materials such as cotton and other soft materials absorbs wave sounds. When this waves are absorbs sound cannot be heard.
For this reason, houses with carpet are much quieter because carpet absorbs sound wave better than hardwood, and tiles.  
</span>
Usimov [2.4K]3 years ago
4 0

The answer is A) Absorption

It's very simple to be honest do you hear thumps when you walk on something thats tile or hardwood like you do on carpet floor?

NoPe

Thank you carpet!

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Given the following data;

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A helicopter carrying Dr. Evil takes off with a constant upward acceleration of 5.0 m/s2. Secret agent Austin Powers jumps on ju
denpristay [2]

Answer:

a) h=250\ m

b) \Delta h=0.0835\ m

Explanation:

Given:

  • upward acceleration of the helicopter, a=5\ m.s^{-2}
  • time after the takeoff after which the engine is shut off, t_a=10\ s

a)

<u>Maximum height reached by the helicopter:</u>

using the equation of motion,

h=u.t+\frac{1}{2} a.t^2

where:

u = initial velocity of the helicopter = 0 (took-off from ground)

t = time of observation

h=0+0.5\times 5\times 10^2

h=250\ m

b)

  • time after which Austin Powers deploys parachute(time of free fall), t_f=7\ s
  • acceleration after deploying the parachute, a_p=2\ m.s^{-2}

<u>height fallen freely by Austin:</u>

h_f=u.t_f+\frac{1}{2} g.t_f^2

where:

u= initial velocity of fall at the top = 0 (begins from the max height where the system is momentarily at rest)

t_f= time of free fall

h_f=0+0.5\times 9.8\times 7^2

h_f=240.1\ m

<u>Velocity just before opening the parachute:</u>

v_f=u+g.t_f

v_f=0+9.8\times 7

v_f=68.6\ m.s^{-1}

<u>Time taken by the helicopter to fall:</u>

h=u.t_h+\frac{1}{2} g.t_h^2

where:

u= initial velocity of the helicopter just before it begins falling freely = 0

t_h= time taken by the helicopter to fall on ground

h= height from where it falls = 250 m

now,

250=0+0.5\times 9.8\times t_h^2

t_h=7.1429\ s

From the above time 7 seconds are taken for free fall and the remaining time to fall with parachute.

<u>remaining time,</u>

t'=t_h-t_f

t'=7.1428-7

t'=0.1428\ s

<u>Now the height fallen in the remaining time using parachute:</u>

h'=v_f.t'+\frac{1}{2} a_p.t'^2

h'=68.6\times 0.1428+0.5\times 2\times 0.1428^2

h'=9.8165\ m

<u>Now the height of Austin above the ground when the helicopter crashed on the ground:</u>

\Delta h=h-(h_f+h')

\Delta h=250-(240.1+9.8165)

\Delta h=0.0835\ m

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