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pashok25 [27]
3 years ago
14

It is possible for an excited hydrogen atom to return to the ground state by the emission of a single photon. regardless of the

initial excited state, this electron transition produces a spectral line in which region of the electromagnetic spectrum?
1. ultraviolet
2. infrared
3. visible light
4. radio waves
Physics
1 answer:
RSB [31]3 years ago
8 0

Answer:

1. Ultraviolet

Explanation:

This is called the Balmer series. Transitions ending in the ground state (n = 1) are called the Lyman series, but the energies released are so large that the spectral lines are all in the ultraviolet region of the spectrum.

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If an object is dropped from a tall building and hits the ground 3.0 s. later, what is the magnitude of the object's displacemen
marin [14]

Find the velocity of the object after one second.  

v = vo + at  

v = (0 m/s) + (9.8 m/s^2)(1 s)  

v = 9.8 m/s  

Now, using that, you can find the displacement in that one second between 1 and 2.  

d = vot + (1/2)at^2  

d = (9.8 m/s)(1 s) + (1/2)(9.8 m/s^2)(1 s)^2  

d = 14.7 m  


5 0
3 years ago
Read 2 more answers
Throughout the reflection, make sure you have a
7nadin3 [17]

Answer:

The dependent variable is the variable that is studied while the independent variable is the variable that is being manipulated

8 0
3 years ago
A soccer ball is kicked with a speed of 22m/s at an angle of 35.0º above the horizontal. If the ball lands at the same level fro
Lisa [10]

Answer:

2.57 seconds

Explanation:

The motion of the ball on the two axis is;

x(t) = Vo Cos θt

y(t) = h + Vo sin θt - 1/2gt²

Where; h is the initial height from which the ball was thrown.

Vo is the initial speed of the ball, 22 m/s , θ is the angle, 35° and g is the gravitational acceleration, 9.81 m/s²

We want to find the time t at which y(t) = h

Therefore;

y(t) = h + Vo sin θt - 1/2gt²

Whose solutions are, t = 0, at the beginning of the motion, and

t = 2 Vo sinθ/g

  = (2 × 22 × sin 35°)/9.81

  = 2.57 seconds

6 0
3 years ago
A single-turn circular loop of wire of radius 5.0 cm lies in a plane perpendicular to a spatially uniform magnetic field. During
Artemon [7]

Answer:

Induced EMF,\epsilon=0.0143\ volts

Explanation:

Given that,

Radius of the circular loop, r = 5 cm = 0.05 m

Time, t = 0.0548 s

Initial magnetic field, B_i=200\ mT=0.2\ T

Final magnetic field, B_f=300\ mT=0.3\ T

The expression for the induced emf is given by :

\epsilon=\dfrac{d\phi}{dt}

\phi = magnetic flux

\epsilon=\dfrac{d(BA)}{dt}

\epsilon=A\dfrac{d(B)}{dt}

\epsilon=A\dfrac{B_f-B_i}{t}

\epsilon=\pi (0.05)^2\times \dfrac{0.3-0.2}{0.0548}

\epsilon=0.0143\ volts

So, the induced emf in the loop is 0.0143 volts. Hence, this is the required solution.

5 0
3 years ago
You want to describe the harmonic motion of a swing. You find out that it takes 2 seconds for the swing to complete one cycle. W
vazorg [7]

Answer: Frequency= 0.5 Hz

Period= 2s

Explanation:

2 sec= 0.5 Hz

0.5Hz= 2 sec

4 0
4 years ago
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