There is a strong, negative relationship between outside temperature and snow shovel sales. As x increases, y decreases.
1/3 of the dimensions means to divide the dimensions by 3. This is to figure out what 1/3 of the dimensions are.
Our length is 6, and our width is 9.
Let's divide our length first.
6/3 = 2.
Our length with 1/3 of it's original dimensions is 2.
Let's divide our width now.
9/3 = 3.
Our width with 1/3 of it's original dimensions is 3.
Our dimensions are 2 by 3.
Your answer is A.) 2 in. by 3 in.
I hope this helps!
Answer:
I cant help unless i have workable units (0.5) is not a point
but im guessing that you were trying to say (0,5) in which case its
7.07106781187
its a triangle
5 on one side
5 on the other
solve for the hypotenuse
hypotenuse = 
hypotenuse = 7.07106781187
I hope this helps!
Answer:
(1, 3)
Step-by-step explanation:
You are given the h coordinate of the vertex as 1, but in order to find the k coordinate, you have to complete the square on the parabola. The first few steps are as follows. Set the parabola equal to 0 so you can solve for the vertex. Separate the x terms from the constant by moving the constant to the other side of the equals sign. The coefficient HAS to be a +1 (ours is a -2 so we have to factor it out). Let's start there. The first 2 steps result in this polynomial:
. Now we factor out the -2:
. Now we complete the square. This process is to take half the linear term, square it, and add it to both sides. Our linear term is 2x. Half of 2 is 1, and 1 squared is 1. We add 1 into the set of parenthesis. But we actually added into the parenthesis is +1(-2). The -2 out front is a multiplier and we cannot ignore it. Adding in to both sides looks like this:
. Simplifying gives us this:

On the left we have created a perfect square binomial which reflects the h coordinate of the vertex. Stating this binomial and moving the -3 over by addition and setting the polynomial equal to y:

From this form,

you can determine the coordinates of the vertex to be (1, 3)
Answer:
0<x<1
Step-by-step explanation:
(x+3)(x−4)<−12
FOIL
x^2 -4x+3x -12 <-12
x^2 -x -12 <-12
Add 12 to each side
x^2 -x -12+12 <-12+12
x^2 -x <0
Factor out an x
x(x-1) <0
Using the zero product property
x(x-1) =0
x=0 x-1=0
x=0 x=1
Check the ranges
x<0
x(x-1) <0
- * - >0
False
0<x<1
x(x-1) <0
+ * - <0
True
x>1
x(x-1) <0
+ * + >0
False