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dexar [7]
3 years ago
15

The circle with center (1,5) and radius 4 has equation

Mathematics
1 answer:
Gala2k [10]3 years ago
5 0
<span>x2</span>+<span>y2</span>+6x+10y+9=<span>0
that is ur answer :)</span>
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50 pts!!!! Luciana's laptop has 3,000 pictures. The size of the pictures is skewed to the right, with a mean of 3.7MB and a stan
skelet666 [1.2K]

Answer:

<u></u>

  • <u>Part A: No, you cannot.</u>

<u></u>

  • <u>Part B: 0.4491</u>

Explanation:

<u>Part A:</u>

The mean of samples of symmetrical (bell shaped) distributions follow a normal distribution pattern.

Thus, for symmetrical distributions you can use the z-score tables to make calculations that permit calculate probabilities for particular values.

For <em>skewed </em>distributions, in general, the samples do not follow a normal distribution pattern, except that the samples are large.

Since <em>a sample of 20 pictures</em> is not large enough, the answer to this question is negative: <em>you cannot accurately calculate the probability that the mean picture size is more than 3.8MB for an SRS (skewed right sample) of 20 pictures.</em>

<u>Part B.</u>

For large samples, the<em> Central Limit Theorem</em> will let you work with samples from skewed distributions.

Although the distribution of a population is skewed, the <em>Central Limit Theorem</em> states that  large samples follow a normal distribution shape.

It is accepted that samples of 30 data is large enough to use the <em>Central Limit Theorem.</em>

Hence, you can use the z-core tables for standard normal distributions to calculate the probabilities for a <em>random sample of 60 pictures</em> instead of 20.

The z-score is calculated with the formula:

  • z-score = (value - mean/ (standard deviation).
  • z=(x-\mu )/\sigma

Here, mean = 3.7MB, value = 3.8MB, and standard deviation = 0.78MB.

Thus:

         z=(3.7M-3.8MB)/(0.78MB)=-0.128

Then, you must use the z-score table to find the probability that the z-score is greater than - 0.128.

There are tables that show the cumulative probability in the right end and tables that show the cumulative probability in the left end of a normal standard distribution .

The probability that a z-score is greater than -0.128 is taken directly from a table with the cumulative probability in the left end. It is 0.4491.

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Answer:
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5 x 5 = 25
6 x 1 = 6
Simplify
25/6 = 4 1/6
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Step-by-step explanation:


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