Answer:
the period of the 16 m pendulum is twice the period of the 4 m pendulum
Explanation:
Recall that the period (T) of a pendulum of length (L) is defined as:
where "g" is the local acceleration of gravity.
SInce both pendulums are at the same place, "g" is the same for both, and when we compare the two periods, we get:
therefore the period of the 16 m pendulum is twice the period of the 4 m pendulum.
The answer is Graph C. To explain, this is because as we look at the position vs time graph, we see that after the first second, it was 30 meters from the start. That would mean that it took 1 second to get to 30 meters. That is shown in Graph c
The charge present determines a force to be attractive or repulsive.
The charges acquired by two bodies determines the Force as Attractive Or Repulsive.
Electric Force applied due to Electrical charges is same in magnitude but opposite in direction. This corresponds this phenomenon equivalent to the Newton's Third Law.
Examples of the experiments and observations:
- On combing hair through a comb and then keeping it close to small pieces of paper shows attraction of paper pieces towards the comb.
This occurs due to the Electric charges present in the comb that induces charge in paper pieces leading to their attraction.
- In both Gravitational Force and Coulomb force, the force remains inversely proportional to the square of the distance following the Inverse Square Law being the Central Force system. This only differs by the fact that in Gravitational Force, masses are used and in Coulomb force, charges are used.
The more the distance between the charges, the less is the Electric Force.
The lesser the distance between the charges, the more is the Electric Force.
If both the objects are charged the same i.e. either positive or negative then the Force is Repulsive and if the charges are Oppositely charged then the force is attractive.
Hence, the charge present determines a force to be attractive or repulsive.
Learn more about Coulomb Force here, brainly.com/question/15451944
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Answer:
The apparent weight of the object is 0.465 N.
Explanation:
Given that,
Weight = 0.71 N
Water level = 50 mL
object inserted = 75 mL
We need to calculate the volume of solid
Using formula of volume
We need to calculate the buoyancy force
Using formula of buoyancy force
Put the value into the formula
We need to calculate the apparent weight of the object
Using formula of apparent weight
Put the value into the formula
Hence, The apparent weight of the object is 0.465 N.
