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Korolek [52]
3 years ago
7

A 45 kg merry go round worker stands on the rides platform 6.3 m from the center. If her speed as she goes around the circle is

4.1 m/s, what is the force of friction necessary to keep her from falling off the platform?
Physics
1 answer:
grin007 [14]3 years ago
7 0
I’ve got 120 n, hope it helps!

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How are different types of radiation arranged along the electromagnetic spectrum
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In order of increasing frequency: Radio, Microwaves, Infrared, Visible light, Ultra-violet, X-rays, Gamma rays. To remember this try:
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3 years ago
In 1993, Cuban athlete Javier Sotomayor set the world record for the high jump. The gravitational potential energy associated wi
Katarina [22]

Answer:2.541

Explanation:

Well , Potential Energy = mgh

m=mass = 82

g=acceleration of gravity=9.80m/s^2

h=what we are looking for

PE=mgh

PE/(mg) = h

Substitute in the values:

1970/(82 x 9.8) = h 2.541

5 0
4 years ago
A person gives a shopping cart an initial push along a horizontal floor to get it moving, and then lets go. The cart travels for
mash [69]

Answer:

Only a backward force is acting, no forward force.

Explanation:

  • Once released from the initial push, in absence of friction, the shopping cart would continue moving forward at a constant speed forever.
  • As it would move at a constant speed, no net force would be acting on it.
  • So, if it is gradually slowing, there must  be a net force producing an acceleration in a direction opposite to the movement.
  • This force is the kinetic friction force, and is the only force acting on the cart in the horizontal direction.
  • As any friction force, opposes to the relative movement between the cart and the horizontal floor, which means that is directed backward.
  • This is consistent with the direction of the acceleration of the cart.
8 0
3 years ago
I don’t know how to answer this question? Can anyone help?
VMariaS [17]

Answer:

F=ma

here F is force, m is mass and a is accelaration,

According to the question,

F=3*F= 3F

m= 1/3 of m= m/3

a= ?

so the equation becomes,

3F= m/3*a

3F*3= ma

9F=ma

F= ma/9

Therefore accelaration reduces by 1/9.

I am not very sure.

7 0
3 years ago
The length of second, s pendulum at a place where gravitational acceleration ]g] is 9.8 m/s
amm1812
O.99 m long .simple pendulum time period is 2s for second formula then use formula T=2pi.rt(lenght/gravity)
6 0
3 years ago
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