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kiruha [24]
2 years ago
8

What does vf stand for a.fringe velocity b.first velocity c.final velocity

Physics
1 answer:
Elza [17]2 years ago
5 0
The correct answer is C. Final Velocity

Hope this helped!
You might be interested in
2. A 50 kg diver is standing on the edge of a 15 m high cliff. What is his potential energy?
Lera25 [3.4K]

Answer:

3675 J

Explanation:

Gravitational Potential Energy = \frac{1}{2} × mass × g × height

( g is the gravitation field strength )

Mass = 50 kg

G = 9.8 N/kg ( this is always the same )

Height = 15 m

Gravitational Potential Energy = \frac{1}{2} × 50 ×9.8 × 15

= 3675 J

3 0
2 years ago
a 10kg cement block horizontally at 6 m/s plows into a bank of sand and comes to a stop in 2.0 m/s. What is the average impact f
Gnesinka [82]
I assume the block plows into the bank of sand with a velocity of 6 m/s and comes to a stop in 2 s.

\bar Ft =  \Delta mv  \\  \\  \bar F =  \frac{\Delta mv }{t}  \\  \\  \bar F \ avarage \ Force \\  m \ momentum \\ v \ velocity \\ t \ time
7 0
3 years ago
Muscles covert chemicals energy int
Elza [17]

Answer:

Mechanical energy

Explanation:

Mechanical energy is needed for movement of objects. Muscles convert chemical energy provided by the rest of the body to allow movement.

8 0
3 years ago
how many kilograms off mercury would fill a 5litre container if the density of mercury is 13.6grams per cm3
Sidana [21]

Answer:

68kg

Explanation:

1 cm^3 is the same as 1 mL and there are 5000mL in 5L

Therefore if the density is 13.6g/mL we multiply 13.6 by 5000 to get the amount of grams required = 68000g which is 68kg

7 0
3 years ago
Assuming that each nucleus is roughlyspherical and that its mass is roughly equal to A (in atomic mass units {\rm u}), what is t
lara [203]

Answer:

ρ/ρ2 = 3 / R₀       the two densities are different

Explanation:

Density is defined as

       ρ = M / V

As the nucleus is spherical

       V = 4/3 π r³

Let's replace

      ρ = A / (4/3 π R₀³)

      ρ = ¾ A / π R₀³

b)

      ρ2 = F / area

The area of ​​a sphere is

     A = 4π R₀²

     ρ2 = F / 4π R₀²

     ρ2 = F / 4π R₀²

Atomic number is the number of protons in the nucleon in not very heavy nuclei. This number is equal to the number of neutrons, but changes in heavier nuclei, there are more neutrons than protons.

Let's look for the relationship of the two densities

     ρ/ρ2 = ¾ A / π R₀³ / (F / 4π R₀²)

     ρ /ρ2 = 3 (A / F) (1 / R₀)

In this case it does not say that the nucleon number is A (F = A), the relationship is

     ρ/ρ2 = 3 / R₀

I see that the two densities are different

3 0
3 years ago
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