Answer:
The velocity is 
Henrietta is at distance
from the under the window
Explanation:
From the question we are told that
The speed of Henrietta is 
The height of the window from the ground is 
Generally the time taken for the lunch to reach the ground assuming it fell directly under the window is

=>
=>
Generally the time taken for the lunch to reach Henrietta is mathematically represented as

Here
is the time duration that elapsed after Henrietta has passed below the window the value is given as 4 s
Now
=>
Generally the distance covered by Henrietta before catching her lunch is

=> 
=> 
Generally the speed with which Bruce threw her lunch is mathematically represented as


Option D) A drop of mercury is both a pure substance and and element.
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Total distance covered is 47.1 m whereas displacement is zero.
<h3>Calculation:</h3>
Given,
Diameter, d = 5 m
No. of revolutions = 3
Radius, r = 5/2 = 2.5 m
To find,
Distance =?
Displacement =?
Distance covered in one revolution = 2πr
Put the values in this,
Distance = 2 × 3.14 × 2.5
= 15.7 m
Total distance covered in 3 revolution = 3 × 31.4
= 47.1 m
Displacement is the change in the position of the object or the distance between the initial and final position.
After 3 revolutions the particle comes back to its initial position. Therefore, the displacement is zero.
Hence, the total distance covered in 3 resolutions is 47.1 m whereas displacement is zero.
Learn more about distance and displacement here:
brainly.com/question/3243551
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Either 25% or 75%. does it to how much is wasted or the difference in the input and waste?
Explanation:
We want to find the statement that is proven by the fact that the balls reach the same height.
A isn't supported by the evidence. Balls can reach the same height without having the same initial speed.
B isn't supported by the evidence. Balls can reach the same height without having the same launch angle.
C is supported. Projectiles spend the same amount of time going up as they do coming down, so if two projectiles reach the same height, then they must spend the same amount of time in the air.
D isn't supported by the evidence. Balls thrown at the same speed and complementary angles have the same range but different heights.
E isn't supported by the evidence. The mass of the ball doesn't affect the height.