Answer:
a) y = 162.6 m
, b) R = 928.64 m
Explanation:
We will solve this exercise using projectile launch kinematics, as the initial velocities and angle are equal on the planet and the Earth, let's look for the gravedd coinage of the planet
Earth
R = v₀² sin 2θ / g
R g = v₀² sin 2θ
In the planet
4.8 R = v₀² sin 2θ /
4.8 R = v₀² sin 2θ
4.8 R = R g
= g / 4.8
= 9.8 / 4.8
= 2.04 m / s²
Now we can answer the questions
a) The maximum height
Vy² = ² - 2 g y
For ymax the vertical speed is zero ( = 0)
sin θ = /
= sinθ
= 44.9 sin 35
= 25.75 m/s
y = ²/2
y = 25.75² / (2 2.04)
y = 162.6 m
b) the scope
R = v₀² sin 2θ /
R = 44.9² sin 2 35 / 2.04
R = 928.64 m
Answer:
a lo que estás viendo me parece que es 80% por qué si no viene se que soy de sexto de primaria
I expect that they will <em>add</em>, and their effect at every location will be the <em>sum</em> of their individual effects at that location.
For example:
If they're acting at the same point and in opposite directions, the effect will be the same as a single force at that point, with strength equal to their difference, and in the direction corresponding to whichever one is stronger.
Answer:
14 m/s
Explanation:
The following data were obtained from the question:
Mass = 50 kg
Initial velocity (u) = 0 m/s
Height (h) = 10 m
Acceleration due to gravity (g) = 9.8 m/s²
Final velocity (v) =?
The velocity (v) with which the person hit the water can be obtained as shown below:
v² = u² + 2gh
v² = 0² + (2 × 9.8 × 10)
v² = 0 + 196
v² = 196
Take the square root of both side
v = √196
v = 14 m/s
Therefore, he will hit the water with a speed of 14 m/s