answer: in pic
explanation: found it here http://gaaq.weebly.com/uploads/7/8/8/4/78844490/chapter_11_q_as.pdf
<span>The most likely type of star to be found in the halo are stars classified as M stars. These stars absorb red light, have temperatures under 3000K, have an average mass of .3 times the mass of the sun, have an average radius of .4 times the radius of the sun, and have .04 times the luminosity of the sun.</span>
Consider the gas to be an ideal gas (it will obey all the introductory gas laws). Also you have to note that the gas will not change phase. It won't.
T_s (Temperature Start) = 95.3o C = 95.3 + 273 = 368.3 oK (degrees Kelvin)
T_e (Temperature End) = 0o C + 273 = 273 oK
Initial volume = Vi = 1.55 mL (no need to change to Liters. The answer will be in mL
Vi /Ts = Ve / Vs Ve is the unknown volume that you seek.
1.55 / 368.3 = Ve / 273
Ve = 1.55 * 273 / 368.3
Ve = 1.1489 mL
If your teacher is concerned about Sig digs, then 0.0 has only two.
Your answer should be 1.1 mL, but I'll give you the choice.
Answer:
4.41 m/s^2
Explanation:
(v_f)^2 - (v_i)^2 = 2a * change in distance
(21)^2 - (0)^2 = 2a * 50
a = (21^2)/(2*50)
a = 4.41 m/s^2
