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3 years ago

An IGCSE student thinks it may be possible to identify different rocks (A, B and C) by measuring their

Physics

1 answer:

kherson [118]3 years ago

8 0

Answer:

See the answer below

Explanation:

a. The volume in the first measuring cylinder reads 70 $cm^3$ while that of the second reads 95 $cm^3$ . Hence;

V1 = 70 $cm^3$

V2 = 95 $cm^3$

b. <u>An object will always displace its own volume in a liquid</u>. Hence:

Volume V of the rock sample = V2 - V1

= 95 - 70 = 25 $cm^3$

c. Mass of A = 102 g

Volume of A = 25 $cm^3$

<em>Density = mass/volume</em>

Hence, density of A = 102/25 = 4.08 g/ $cm^3$

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Ivanshal [37]

Answer:

Part a)

$f_w = f_g = 4.57 \times 10^{14} Hz$

Part b)

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Part c)

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Explanation:

Part a)

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Part b)

As we know that the refractive index of water is given as

$\mu_w = 4/3$

so the wavelength in the water medium is given as

$\lambda_w = \frac{\lambda}{\mu_w}$

$\lambda_w = \frac{656 nm}{4/3}$

$\lambda_w = 492 nm$

Similarly the refractive index of glass is given as

$\mu_w = 3/2$

so the wavelength in the glass medium is given as

$\lambda_g = \frac{\lambda}{\mu_g}$

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Part c)

Speed of the wave in water is given as

$v_w = \frac{c}{\mu_w}$

$v_w = \frac{3 \times 10^8}{4/3}$

$v_w = 2.25 \times 10^8 m/s$

Speed of the wave in glass is given as

$v_g = \frac{c}{\mu_g}$

$v_g = \frac{3 \times 10^8}{3/2}$

$v_g = 2 \times 10^8 m/s$

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Sonbull [250]

Answer:true

Explanation:

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3 years ago

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san4es73 [151]

Answer:

2.9 m

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Next, find the distance it travels in that time.

x = x₀ + v₀ t + ½ at²

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Rounded to two significant figures, the marble travels 2.9 meters in the x direction.

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