Answer:
An IGCSE student thinks it may be possible to identify different rocks (A, B and C) by measuring their
1 answer:
Answer:
See the answer below
Explanation:
a. The volume in the first measuring cylinder reads 70 while that of the second reads 95
. Hence;
V1 = 70
V2 = 95
b. <u>An object will always displace its own volume in a liquid</u>. Hence:
Volume V of the rock sample = V2 - V1
= 95 - 70 = 25
c. Mass of A = 102 g
Volume of A = 25
<em>Density = mass/volume</em>
Hence, density of A = 102/25 = 4.08 g/
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Answer:
x = 0.176 m
Explanation:
For this exercise we will take the condition of rotational equilibrium, where the reference system is located on the far left and the wire on the far right. We assume that counterclockwise turns are positive.
Let's use trigonometry to decompose the tension
sin 60 = / T
T_{y} = T sin 60
cos 60 = Tₓ / T
Tₓ = T cos 60
we apply the equation
∑ τ = 0
-W L / 2 - w x + T_{y} L = 0
the length of the bar is L = 6m
-Mg 6/2 - m g x + T sin 60 6 = 0
x = (6 T sin 60 - 3 M g) / mg
let's calculate
let's use the maximum tension that resists the cable T = 900 N
x = (6 900 sin 60 - 3 200 9.8) / (700 9.8)
x = (4676 - 5880) / 6860
x = - 0.176 m
Therefore the block can be up to 0.176m to keep the system in balance.