rutherford was the first to hypothesize that electrons orbit a positively charged nucleus a. true b.false
1 answer:
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Answer:
The final velocity of the object is, = 27 m/s
Explanation:
Given,
The acceleration of the object, a = 1000 m/s²
The initial displacement of the object, = 0 m
The final displacement of the object, = 0.75 m
The initial velocity of the object will be, = o m/s
The final velocity of the object, = ?
The average velocity of the object,
v = ( -
)/ t
= 0.75 / t
The acceleration is given by the relation
a = v / t
1000 m/s² = 0.75 / t²
t² = 7.5 x 10⁻⁴
t = 0.027 s
Using the I equation of motion,
= u + at
Substituting the values
= 0 + 1000 x 0.027
= 27 m/s
Hence, the final velocity of the object is, = 27 m/s
Answer:
h~=371.26m
Explanation:
when an object falls we use the equations of accelerated motion. There is only one that gives distance.
Since we have no initial velocity (started from rest) we can get rid of the (ut) term
where a we substitute g (gravitational acceleration, constant for given heights and almost 9.81m/s^2).