Ask question

Ask question

All categories

3 years ago

9

Two lab assistants measured a metal rod. One reported the measurement as 250 cm, and the other measured it as 250. cm. These mea

surements are equally precise.
True
False

1 answer:

VladimirAG [237]3 years ago

8 0

The answer is f or false

You might be interested in

Heyy pls help anyone?

madam [21]

1a. calcium chloride (CaCl2)
b. 2HCl (aq) + Ca(OH)2 (s) —> CaCl2 (aq) + 2H2O (l)

i’m not sure about the rest but i hope this helped ^^

7 0

2 years ago

Read 2 more answers

What is the molecular formula of a compound with the empirical formula

ipn [44]

Answer: $C_2H_2O_2$

Explanation:

Molecular formula is the chemical formula which depicts the actual number of atoms of each element present in the compound.

Empirical formula is the simplest chemical formula which depicts the whole number of atoms of each element present in the compound.

The empirical formula is $CHO$

The empirical weight of $CHO$ = 1(12)+1(1)+1(16)= 29 g.

The molecular weight = 60 g/mole

Now we have to calculate the molecular formula:

$n=\frac{\text{Molecular weight}}{\text{Equivalent weight}}=\frac{60}{29}=2$

The molecular formula will be= $2\times CHO=C_2H_2O_2$

Thus molecular formula will be $C_2H_2O_2$

5 0

3 years ago

Question 19-20<br> I’m not really sure, can someone help me

Nesterboy [21]

Hi my name is Jaleesa The answer = -1

6 0

3 years ago

How many liters of O2 at 298 K and 1.00 bar are produced in 1.50 hr in an electrolytic cell operating at a current of 0.0200 A?

stellarik [79]

Answer: 0.0069L

Explanation:

2H2O(l) ---->O2(g) + 4H+(aq) + 4e-

no of moles= it/eF

NO of moles of O2 produced = (Current in Ampere x Time in second)/ (Faraday constant x Number of electrons required)

Moles of O2 produced = (0.02x (60 x 60X1.5 s)/(96485 x 4)

= 0.0002798 moles= 2.798x 10 ^-4moles

Using ideal gas equation,

P V = n R T

Where, P is the pressure,

V is the volume,

n is the number of moles,

R is the gas constant, and T is the temperature

We have, 1 bar = 0.986923 atm

Substituting the values,

V = nRT/P = (2.798 x 10-4moles x 0.08205 L atm mol K x 298 K)/ 0.986923 atm = 0.0069L

Volume of O2 produced = 0.0069L

7 0

3 years ago

Year/ Distance (cm)

luda_lava [24]

Answer:

the answer is C

Explanation:

6.7 to 13.2 then look at the numbers they go up but not a lot each time

5 0

3 years ago