Answer:
5.52 g
Explanation:
First we <u>convert the given masses of both reactants into moles</u>, using their <em>respective molar masses</em>:
- 6.30 g NH₃ ÷ 17 g/mol = 0.370 mol NH₃
- 1.80 g O₂ ÷ 32 g/mol = 0.056 mol O₂
Now we <u>calculate with how many NH₃ moles would 0.056 O₂ moles react</u>, using the<em> stoichiometric coefficients</em>:
- 0.056 mol O₂ *
= 0.045 mol NH₃
As there more NH₃ moles than required, NH₃ is the excess reactant.
Then we calculate how many NH₃ moles remained without reacting:
- 0.370 mol NH₃ - 0.045 mol NH₃ = 0.325 mol NH₃
Finally we convert NH₃ moles into grams:
- 0.325 mol NH₃ * 17 g/mol = 5.52 g
Answer:
Units Accuracy = the degree to which a measurement can be
Column Matter = anything that has mass and occupies
Space Precision = an indication of how close a measurement is to the correct
Replicated Meniscus = the curved top surface of a liquid
Result Density = the mass of an object per unit volume
Volume = space occupied, measured in cubic
Explanation:
In the fields of science , the Unit Accuracy of a measurement system is the degree of closeness of measurements of a quantity to that quantity's true value.
Column Matter can be defined as anything that had mass and occupies space.
Space Precision refers to the closeness of the measurements to each other. It's the quality, condition, or fact of being exact and accurate.
Replicated Meniscus is the curve in the upper surface of a liquid close to the surface of the container or another object, caused by surface tension. It can be either concave or convex, depending on the liquid and the surface.
Result Density can be defined as the mass of an object per unit volume.
Volume: The space occupied by any object is called the volume. The volume of an object is the amount of space occupied by the object. Volume is measured in "cubic units".
C is becsuse it just souds right
Answer:
The final volume will be 5.80 L
Explanation:
Step 1: Data given
Number of moles gas = 0.140 moles
Volume of gas = 2.78 L
Number of moles added = 0.152 moles
Step 2: Calculate the final volume
V1/n1 = V2/n2
⇒ with V1 = the initial volume = 2.78 L
⇒ with n1 = the initial number of moles = 0.140 moles
⇒ with V2 = The new volume = TO BE DETERMINED
⇒ with n2 = the new number of moles = 0.140 + 0.152 = 0.292 moles
2.78/0.140 = V2 /0.292
V2 = 5.80 L
The final volume will be 5.80 L
Ur ans is option d
addition
