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borishaifa [10]
2 years ago
11

The equal areas law is Keplers 2nd law of motion of planetary motion. It states that _____

Chemistry
2 answers:
jeyben [28]2 years ago
7 0

Answer: It states that a line joining a planet and the sun sweeps an equal area in equal time, moving along its orbit.

Explanation: It tells us about the speed of a planet revolving around the sun in an elliptical orbit. The speed of the planet varies inversely to the distance, when the planet is closer speed is high and speed is low when it recedes from the sun. The rate at which area is being swept out is constant ,that is 'equal area in equal time'.  

seraphim [82]2 years ago
6 0

An imaginary line joining a planet and the sun sweeps out an equal area of space in equal amounts of time. Thus, the speed of the planet increases as it nears the sun and decreases as it recedes from the sun.

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C12H22O11 is an example of a(n):
ycow [4]

Answer:

molecular compound

Explanation:

it has two or more nonmetal elements and are covalently bonded

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2 years ago
What is the mass in grams of 7.23 miles of dinitrogen trioxide?
nevsk [136]

Answer:

549.563868

Explanation:

1 mole is equal to 1 moles N2O3, or 76.0116 grams. so 76.0116 x 7.23 = 549.563868

3 0
3 years ago
How many electrons would Lithium with a -1 charge have?
Helen [10]

Answer:

lithium=atomic no.=3

Explanation:

-1 charge on lithium means one electron has added to it .Thus,

  Li-1=no. of electrons=3+1=4

3 0
3 years ago
Nothing sus please haha<br> http://quizprank.xyz/message.php?id=n8q76jgf
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lol thanks for the point btws! i really needed them for my math test questions have a good day btw! good vibes!

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8 0
3 years ago
To determine the enthalpy and entropy of dissolving a compound, you need to measure the Ksp at multiple _______. Then, plot ln(K
Aloiza [94]

Answer:

To determine the enthalpy and entropy of dissolving a compound, you need to measure the Ksp at multiple temperatures. Then, plot ln(Ksp) vs. 1/T. The slope of the plotted line relates to the enthalpy (ΔH) of dissolving and the intercept of the plotted line relates to the entropy (ΔS) of dissolving.

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us use the thermodynamic definition of the Gibbs free energy and its relationship with Ksp as follows:

\Delta G=-RTln(Ksp)\\\\\Delta G=\Delta H-T\Delta S

Thus, by combining them, we obtain:

-RTln(Ksp)=\Delta H-T\Delta S\\\\ln(Ksp)=-\frac{\Delta H}{RT} +\frac{T\Delta S}{RT} \\\\ln(Ksp)=-\frac{\Delta H}{RT} +\frac{\Delta S}{R}

Which is related to the general line equation:

y=mx+b

Whereas:

y=ln(Ksp)\\\\m=-\frac{\Delta H}{R} \\\\x=\frac{1}{T} \\\\b=\frac{\Delta S}{R}

It means that we answer to the blanks as follows:

To determine the enthalpy and entropy of dissolving a compound, you need to measure the Ksp at multiple temperatures. Then, plot ln(Ksp) vs. 1/T. The slope of the plotted line relates to the enthalpy (ΔH) of dissolving and the intercept of the plotted line relates to the entropy (ΔS) of dissolving.

Regards!

8 0
2 years ago
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