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borishaifa [10]
2 years ago
11

The equal areas law is Keplers 2nd law of motion of planetary motion. It states that _____

Chemistry
2 answers:
jeyben [28]2 years ago
7 0

Answer: It states that a line joining a planet and the sun sweeps an equal area in equal time, moving along its orbit.

Explanation: It tells us about the speed of a planet revolving around the sun in an elliptical orbit. The speed of the planet varies inversely to the distance, when the planet is closer speed is high and speed is low when it recedes from the sun. The rate at which area is being swept out is constant ,that is 'equal area in equal time'.  

seraphim [82]2 years ago
6 0

An imaginary line joining a planet and the sun sweeps out an equal area of space in equal amounts of time. Thus, the speed of the planet increases as it nears the sun and decreases as it recedes from the sun.

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In the Dumas Method, the volatile sample
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Answer:

true

Explanation:

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2 years ago
A gas that exerts a pressure of 537 torr in a container with a volume of 5.30 L will exert a pressure of 255 torr when transferr
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Answer:- The gas needs to be transferred to a container with a volume of 11.2 L.

Solution:- From Boyle's law. "At constant temperature, Volume is inversely proportional to the pressure."

It means, the volume is decreased if the pressure is increased and vice versa.

Here, the Pressure is decreasing from 537 torr to 255 torr. So, the volume must increase and calculated by using the equation:

P_1V_1=P_2V_2

Where, P_1 is initial pressure and P_2 is final pressure. Similarly, V_1 is initial volume and V_2 is final volume.

Let's plug in the values in the equation:

(537 torr)(5.30 L) = (255 torr)(V_2)

V_2=(\frac{537 torr*5.30 L}{255 torr})

V_2 = 11.2 L

So, the new volume of the container needs to be 11.2 L.

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3 years ago
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3 years ago
How do you work out question 1a?
Sliva [168]

Answer:

-125 kJ

Explanation:

You calculate the energy required to break all the bonds in the reactants. Then you subtract the energy to break all the bonds in the products.

                     H₂C=CH₂   +    H₂ ⟶    H₃C-CH₃

Bonds:       4C-H + 1C=C     1H-H     6C-H + 1C-C

D/kJ·mol⁻¹:  413       612        436       413      347

The formula relating ΔHrxn and bond dissociation energies (D) is

ΔHrxn = Σ(Dreactants) – Σ(Dproducts)

(Note: This is an exception to the rule. All other thermochemical reactions are “products – reactants”. With bond energies, it’s “reactants – products”. The reason comes from the way we define bond energies.)

<em>For the reactant</em>s:

Σ(Dreactants) = 4 × 413 + 1 × 612 + 1 × 436 = 2700 kJ

<em>For the products:</em>

Σ(Dproducts) = 6 × 413 + 1 × 347 = 2825 kJ

<em>For the system</em> :

ΔHrxn = 2700 - 2825 = -125 kJ

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