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Juliette [100K]
3 years ago
11

In the chemical formula below, how many H atoms are present? SNH4OH

Chemistry
1 answer:
saul85 [17]3 years ago
3 0

Answer:

I believe there is 2 but I could be wrong so really sorry if I am

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Answer:

1. (NH₄)₂S(s) -----> NH₄+(aq) + S²-(aq)

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Explanation:

The dissociation of ammonium sulphide, (NH₄)₂S when dissolved in water is given in the equation below:

(NH₄)₂S(s) -----> NH₄+(aq) + S²-(aq)

However very little S²- ions are present in solution due to the very basic nature of the S²- ion (Kb = 1 x 105).

The ammonium ion being a better proton donor than water, donates a proton to sulphide ion to form hydrosulphide ion which exists in equilibrium with aqueous ammonia.

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2. The reaction between aluminium nitrate and sodium phosphatein aqueous solution is a double decomposition reaction whish results in the precipitation of insoluble aluminium phosphate. The equation of the reaction is given below :

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The net ionic equation is given below:

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What ion must be present for a compound to be considered a base?
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CH2OHCH2OH is a general example of a polyhydroxyl alcohol. A polyhydroxyl alchol is one in which there are two hydroxyl groups present in the substance. The –OH group attached to both the carbon atoms.

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Explanation:

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