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PtichkaEL [24]
3 years ago
6

how many grams of bromine, br2, are required to react completely with 37.4 grams of aluminum chloride, AlCl3?

Chemistry
1 answer:
STatiana [176]3 years ago
8 0
The reaction of bromine with aluminum chloride will bring about the formation of aluminum bromide and chlorine through a single-replacement reaction. This can be expressed in a balanced chemical reaction,

      3Br₂ + 2AlCl₃ --> 2AlBr₃ + 3Cl₂

This means that 3 moles of Br₂ which is equal to 159.1 g is required to react with 2 moles of AlCl₃ or equal to 266.68 g. Using this and the given above,

      mass of bromine = (37.4 grams AlCl3)(159.1 g of Bromine/266.68 g of AlCl3)
      Mass of bromine = 22.31 grams of Br₂

<em>Answer: 22.31 grams</em>
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ether has a density of 0.736 g/cm^3 at 20 degrees C. what is the volume, in liters, of 225.0 grams of ether?
polet [3.4K]
D = m / V

0.736 = 225.0 / V

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Dinitrogen pentoxide can be made by the reaction of nitrogen with oxygen. Consider the reaction
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3 years ago
SOLVE The density of a gas is 0.68 g/mL. What amount of space would 23.8 g of this gas occupy?
Contact [7]

Answer:

<h2>The answer is 35 mL</h2>

Explanation:

Density of a substance can be found by using the formula

Density(\rho) =  \frac{mass}{volume}

From the question we are finding the amount of space the gas will occupy that's the volume of the gas

Making volume the subject we have

volume =  \frac{mass}{Density}

From the question

mass = 23.8 g/mL

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Substitute the values into the above formula and solve

That's

volume =  \frac{23.8}{0.68}

We have the final answer as

<h3>35 mL</h3>

Hope this helps you

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Explanation:

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