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PtichkaEL [24]
3 years ago
6

how many grams of bromine, br2, are required to react completely with 37.4 grams of aluminum chloride, AlCl3?

Chemistry
1 answer:
STatiana [176]3 years ago
8 0
The reaction of bromine with aluminum chloride will bring about the formation of aluminum bromide and chlorine through a single-replacement reaction. This can be expressed in a balanced chemical reaction,

      3Br₂ + 2AlCl₃ --> 2AlBr₃ + 3Cl₂

This means that 3 moles of Br₂ which is equal to 159.1 g is required to react with 2 moles of AlCl₃ or equal to 266.68 g. Using this and the given above,

      mass of bromine = (37.4 grams AlCl3)(159.1 g of Bromine/266.68 g of AlCl3)
      Mass of bromine = 22.31 grams of Br₂

<em>Answer: 22.31 grams</em>
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Which atomic models does Rutherford’s experimental evidence support? Explain why these models (Dalton, Bohr, Thomson models) are
ipn [44]

Answer:

Rutherford was the first scientist who proposed the nuclear model of the atom. According to his atomic model, most of the space of an atom is empty, while the nucleus containing protons and neutrons lie at the center of the atom while electrons revolve around nucleus in definite orbits.

If we talk about studies of some other scientists like Dalton, Neil Bohr and JJ Thomson, they all are compatible with Rutherford's results to a large extent.

For example: Dalton's atomic model assumed that atoms of any substance are similar in size and atoms react to form compounds. Rutherford's concept indicated that atoms contain electrons and they are in a specific number which can be shared to form compounds.

If we talk about Bohr's model, it states that electrons revolve around nucleus in specific shells, this again is compatible with Rutherford's results which gave the concept of shells.

If we talk about Thomson's Plum pudding model, that describe atom as negative particles floating within a soup of diffuse positive charge. This is also compatible with the results of Rutherford that state that negative electrons surround positive nucleus.

Rutherford's model was best atomic model but still it took help from many previous studies and therefore was compatible with the results of old models.


Hope it help!

5 0
3 years ago
Read 2 more answers
A certain gas is present in a 10.0 LL cylinder at 4.0 atmatm pressure. If the pressure is increased to 8.0 atmatm the volume of
ICE Princess25 [194]

Answer:

The gas obeys Boyle’s law and the value of k_i\&k_f both are equal to 40.0 atm L.

Explanation:

Initial volume of the gas = V_1=10.0 L

Initial pressure of the gas = P_1=4.0 atm

Final volume of the gas = V_2=5.0 L

Final pressure of the gas = P_2=8.0 atm

This law states that pressure is inversely proportional to the volume of the gas at constant temperature.  

PV=k

The equation given by this law is:

P_1V_1=P_2V_2

P_1\propto \frac{1}{V_1}

P_1V_1=k_i

k_i=4.0 atm\times 10.0 L = 40.0 atm L

P_2\propto \frac{1}{V_2}

P_V_2=k_f

k_f=8.0 atm\times 5.0 L = 40.0 atm L

k_i=k_f=40.0 atm L

The gas in the cylinder is obeying Boyle's law.

The gas obeys Boyle’s law and the value of k_i\&k_f both are equal to 40.0 atm L.

6 0
3 years ago
Question<br> What is the molarity of a 400 mL solution containing 0.60 moles of NaCl?
Mumz [18]

Answer:

0.24 M

Explanation:

Molarity = Moles solute / Liters solution

Step 1: Identify variables

400 mL = Liters solution

0.60 moles = Moles solute

Step 2: Identify conversions

1 L = 1000 mL

Step 3: Convert mL to L

400mL(1 L/1000mL) = 0.4 L

Step 4: Find molarity

M = (0.4 L)(0.60 mol) = 0.24 M

6 0
3 years ago
A 250.0-ml sample of ammonia, nh3 (g), exerts a pressure of 833 torr at 42.4 °c. what mass of ammonia is in the container
Lelu [443]
To solve this, let's assume ideal gas behavior.

PV=nRT
Let's solve for n. Convert units to SI units first.

Pressure = 833 torr(101325 Pa/760 torr) = 111,057.53 Pa
Volume = 250 mL(1 L/1000 mL)(1 m³/1000 L) = 2.5×10⁻⁴ m³
Temperature = 42.4 + 273 = 315.4 K

n = (8,314 J/mol·K)(315.4 K)/(111057.53 Pa)(2.5×10⁻⁴ m³)
n = 94.45 mol

The molar mass of ammonia is 17.031 g/mol.
Mass = 94.45*17.031 = <em>1,608.51 g ammonia</em>


6 0
3 years ago
If the mass of an object is 10 kg and the acceleration of an object due to
mars1129 [50]
Hmm the answer is 2.454

No explanation needed it’s just 2.454
5 0
2 years ago
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