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puteri [66]
3 years ago
13

How many atoms are in 3.8 mol of calcium? Round your answer to 2 decimal places.

Chemistry
1 answer:
Neporo4naja [7]3 years ago
7 0

Answer:

\boxed {\boxed {\sf 2.29 *10^{24} \ atoms \ Ca}}

Explanation:

To convert from moles to atoms, we must use Avogadro's Number.

6.022*10^{23}

This number tells us the number of particles (atoms, molecules, ions, etc.) in 1 mole. In this case, the particles are atoms of calcium (Ca).

6.022*10^{23} \ atoms \  Ca / 1 \ mol \ Ca

1. Convert from moles to atoms.

Write Avogadro's number as a fraction.

\frac {6.022 *10^{23} \ atoms \ Ca} {1 \ mol \ Ca}

Multiply the given number of moles of calcium (3.8) by the fraction created.

3.8 \ mol \ Ca *\frac {6.022 *10^{23} \ atoms \ Ca} {1 \ mol \ Ca}

The moles of calcium will cancel.

3.8 *\frac {6.022 *10^{23} \ atoms \ Ca} {1 }

The denominator of 1 is insignifcant and we can turn this into a simple multiplication problem.

3.8 *  {6.022 *10^{23} \ atoms \ Ca}

2.28836*10^{24} \ atoms \ Ca

2. Round

The problem tells us to round to 2 decimal places or the hundredth place.

2.28836*10^{24} \ atoms \ Ca

The 8 in the thousandth place tells us to round the 8 to a 9.

2.29 *10^{24} \ atoms \ Ca

There are about <u>2.29*10²⁴ atoms of calcium</u> in 3.8 moles.

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Explanation:

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H_3PO_4 is a weak acid and hence will not dissociate into ions whereas LiOH is a strong base and will easily dissociate into ions.

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Net ionic equation becomes:

H_3PO_4(aq.)+3OH^-(aq.)\rightarrow PO_4^{3-}(aq.)+3H_2O(l)

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2HBr(aq.)+Co(OH)_2(aq.)\rightarrow CoBr_2(aq.)+2H_2O(l)

HBr and Co(OH)_2 are strong acid and strong base respectively, hence they will easily dissociate into ions.

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