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3 years ago

What type of ethic is life-centered and views humans as just one component life on Earth

Physics

2 answers:

katrin [286]3 years ago

4 0

The choices can be found elsewhere and as follows:

A anthropocentric

B frontier

C land

D biocentric

I think the correct answer is option A. It is anthropocentric the type of ethic that is life-centered and views humans as just one component life on Earth. Hope this answers the question. Have a nice day.

Natasha2012 [34]3 years ago

4 0

Answer:bio centric

Explanation:

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The radii of curvature of a biconvex lens are 4 cm and 15 cm. The lens is in air, its index of refraction is 1.5. An object is a

rewona [7]

Answer:

v = 6.315 cm

Explanation:

given,

R₁ = 4 cm = 0.04 m

R₂ = 15 cm = 0.15 m

n =1.5

$\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}=(n-1)(\dfrac{1}{R_1}-\dfrac{1}{R_2})$

$\dfrac{1}{v}-\dfrac{1}{-1}=(1.5-1)(\dfrac{1}{0.04}+\dfrac{1}{0.15})$

$\dfrac{1}{v}+1 = 0.5 \times 31.66$

$\dfrac{1}{v} = 15.833$

v = 0.06315 m

v = 6.315 cm

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3 years ago

What is the electric potential at a distance of 1.2 m from a 7.5 UC point charge?

grandymaker [24]

Answer:

A. 5.6x10^4

Explanation:

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3 years ago

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Un reloj de péndulo de largo L y período T, aumenta su largo en ΔL (ΔL << L). Demuestre que su período aumenta en: ΔT = π

Kruka [31]

Answer:

ΔT = $\pi \ \frac{\Delta L}{\sqrt{Lg} }$

Explanation:

In a simple harmonic motion, specifically in the simple pendulum, the angular velocity

w = $\sqrt{\frac{g}{L} }$

angular velocity and period are related

w = 2π / T

we substitute

2π / T = \sqrt{\frac{g}{L} }

T = $2\pi \ \sqrt{\frac{L}{g} }$

In this exercise indicate that for a long Lo the period is To, then and increase the long

L = L₀ + ΔL

we substitute

T = $2\pi \ \sqrt{\frac{L + \Delta L}{g} }$

T = $2\pi \ \sqrt{\frac{L}{g} } \ \sqrt{1+ \frac{\Delta L}{L} }$

in general the length increments are small ΔL/L «1, let's use a series expansion

$\sqrt{1+ \ \frac{\Delta L}{L} } = 1 + \frac{1}{2} \frac{\Delta L}{L} + ...$

we keep the linear term, let's substitute

T = $2\pi \ \sqrt{\frac{L}{g} } \ ( 1 + \frac{1}{2} \frac{\Delta L}{L} )$

if we do

T = T₀ + ΔT

T₀ + ΔT = $2\pi \sqrt{\frac{\Delta L}{g} } + \pi \ \sqrt{\frac{L}{g} } \ \frac{\Delta L}{L}$

T₀ + ΔT = T₀ + $\pi \sqrt{\frac{1}{Lg} } \ \Delta L$

ΔT = $\pi \ \frac{\Delta L}{\sqrt{Lg} }$

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3 years ago

A completely inelastic collision occurs between two balls of wet putty that move directly toward each other along a vertical axi

Marrrta [24]

Answer:

h = 2.64 meters

Explanation:

It is given that,

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Speed of the first ball, $v_1=20\ m/s$ (upward)

Mass of the other ball, $m_2=2\ kg$

Speed of the other ball, $v_2=-12\ m/s$ (downward)

We know that in an inelastic collision, after the collision, both objects move with one common speed. Let it is given by V. Using the conservation of momentum to find it as :

$V=\dfrac{m_1v_1+m_2v_2}{m_1+m_2}$