Answer:
The distance traveled by the skier is 5.309 km
Solution:
As per the question:
Mass of the skier, m = 64 kg
Coefficient of friction between the ski and the snow, 
Mass of snow, M = 5.0 kg
Now,
To calculate the distance, 's' traveled by the skier, in order to melt 5.0 kg of snow:
We know that:

where
= coefficient of friction
N = Normal Reaction
N = mg
Thus
(1)
Also,
(2)
where
= Latent Heat of fusion
Thus from eqn (1) and (2):


s = 5.309 km
Answer:
KE increases and PE decreases
Explanation:
Answer:
b.
Explanation:
-vesign shows the lens is <em><u>C</u></em><em><u>O</u></em><em><u>N</u></em><em><u>C</u></em><em><u>A</u></em><em><u>V</u></em><em><u>E</u></em>
<em><u>f</u></em><em><u>=</u></em>1/power
Point C would the greatest