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mr_godi [17]
3 years ago
10

TAKING TEST NOW NEED ASAP !!

Physics
2 answers:
Margaret [11]3 years ago
7 0

Answer:

c

Explanation:

i dont know

just felt

s344n2d4d5 [400]3 years ago
4 0

Answer:

C

Explanation:

I think that's it. dont know if that's rogue

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Please help!! I will give brainliest!
grandymaker [24]

Answer:

Depends.

Explanation:

Whether the object is going left or right, the speed will stay the same until friction eventually stops it. <em>However, </em>if, for example, we're talking about an object going straight before veering right, then yes, speed <em>does</em> matter. An object will normally have to speed up or slow down momentarily when changing direction to keep itself sustained on the ground.

So, honestly? It really depends on what we're talking about!

Hope this helped!

Source(s) used: None.

7 0
3 years ago
How much force is needed to accelerate a 15kg bowling ball at 2 m/s^2
olga_2 [115]
Golf no doing what I iuroeurir to do my homework and my homework
7 0
3 years ago
Read 2 more answers
a 46 kilogram student climbs 11 meter up a rope at a constant speed if the student power output is 230 watts how long in seconds
Bezzdna [24]
230×46=10580÷11=961 second
3 0
3 years ago
The inner planets are DIFFERENT from the outer planets mainly because they are A) colder. B) larger. C) comprised of gas. D) com
Vaselesa [24]
The inner planets are not colder or larger than the outer ones,
and they're not comprised of gas.

The inner planets are the ones that are made of rock.  ( D ).
3 0
3 years ago
Read 2 more answers
The owner of a company that manufactures drinking cups decides it would be impressive to build an inground swimming pool that is
garri49 [273]

Answer:

The depth is 5.15 m.

Explanation:

Lets take the depth of the pool = h m

The atmospheric pressure ,P = 101235 N/m²

The area of the top = A m²

The area of the bottom =  a m²

Given that A= 1.5 a

The force on the top of the pool = P A

The total pressure on the bottom = P + ρ g h

ρ =Density of the  water = 1000 kg/m³

The total pressure at the bottom of the pool =  (P + ρ g h) a

The bottom and the top force is same

(P + ρ g h) a = P A

P a +ρ g h a =  P A

ρ g h a =  P A - P a

h=\dfrac{P ( A-a)}{\rho g a}

h=\dfrac{P ( 1.5 a-a)}{\rho g a}

h=\dfrac{P ( 1.5- 1)}{\rho g}

h=\dfrac{101235 ( 1.5- 1)}{1000\times 9.81}\ m

h=5.15 m

The depth is 5.15 m.

7 0
3 years ago
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