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mr_godi [17]
3 years ago
10

TAKING TEST NOW NEED ASAP !!

Physics
2 answers:
Margaret [11]3 years ago
7 0

Answer:

c

Explanation:

i dont know

just felt

s344n2d4d5 [400]3 years ago
4 0

Answer:

C

Explanation:

I think that's it. dont know if that's rogue

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how will you connect three resistors of 2 ohm centrioles and 5 ohms respectively so as obtain of the result and the resistance o
victus00 [196]

Two resistor of 2Ω in series parallel to resistor 5Ω in series to a 2Ω resistor. This configuration gives to us an equivalent resistor of 2.55Ω.

To solve this problem we have to use the rules of conection of resistor in series and parallel.

A resistor R1 in serie with other resistor R2 gives us an equivalent resistor Req= R1 + R2.

A resistor R1 in parallel with other resistor R2 gives us an equivalent resistor Req = R1.R2/R1+R2.

The circuit that show an arregement of resistor which we obtain a equivalent resistor of 2.5Ω from three resistor of 2Ω and 5Ω respectively is attached in the image:

3 0
4 years ago
A uniform rod is 2. 0 m long and has mass 15 kg. What is most nearly the rod's mass moment of inertia?
trapecia [35]

The rod's mass moment of inertia is 5kgm².

<h3>Moment of Inertia:</h3>

The "sum of the product of mass" of each particle with the "square of its distance from the axis of rotation" is the formula for the moment of inertia.

The Parallel axis Theorem can be used to compute the moment of inertia about the end of the rod directly or to derive it from the center of mass expression. I = kg m². We can use the equation for I of a cylinder around its end if the thickness is not insignificant.

If we look at the rod we can assume that it is uniform. Therefore the linear density will remain constant and we have;

or = M / L = dm / dl

dm = (M / L) dl

I =  \int\limits^M_0 {r^2} \, dm

I = \int\limits^\frac{L}{2} _\frac{-L}{2}  {I^2 (M/L)} \, dl

Here the variable of the integration is the length (dl). The limits have changed from M to the required fraction of L.

I = \int\limits^\frac{L}{2} _\frac{-L}{2}  {I^2 (M/L)} \, dl

I = \frac{M}3L}[(\frac{L^3}{2^3}   - \frac{-L^3}{2^3} )]\\\\I = \frac{1}{12}ML^2

Mass of the rod = 15 kg

Length of the rod = 2.0 m

Moment of Inertia, I = \frac{1}{12}15 (2)^2

                               = 5 kgm²

Therefore, the moment of inertia is 5kgm².

Learn more about moment of inertia here:

brainly.com/question/14119750

#SPJ4

4 0
2 years ago
Why do you feel warm when you are standing away from a camp fire
olya-2409 [2.1K]
Because the heat of the fire diffuses into the atmosphere and then we absorb it into our body
5 0
3 years ago
A tennis ball moves 16 meters northward, then 22 meters southward, then 12 meters northward, and finally 32 meters southward.
igomit [66]
U didn’t ask a question so I’ll just say that’s cool that it moves like that
8 0
3 years ago
The loudness of a sound will be determined by its
adoni [48]

Answer:

By its amplitude.

Explanation:

loudness is sound intensity & intensity depends on square of amplitude. for example higher the amplitude higher the intensity which means higher the loudness.

4 0
3 years ago
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