3 years ago

A runner begins from rest and accelerates at a rate of 0.22 meters per second' for 15

Physics

1 answer:

ziro4ka [17]3 years ago

7 0

Answer:

25 m

Explanation:

Given:

v₀ = 0 m/s

a = 0.22 m/s²

t = 15 s

Find: Δx

Δx = v₀ t + ½ at²

Δx = (0 m/s) (15 s) + ½ (0.22 m/s²) (15 s)²

Δx = 24.75 m

Rounded to two significant figures, the runner moves a distance of 25 m.

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