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4 years ago

Which formula represents an unsaturated hydrocarbon? (1) C5H12 (3) C7H16 (2) C6H14 (4) C8H14

Chemistry

2 answers:

Alik [6]4 years ago

7 0

Answer:

Answer is C₈H₁₄

Explanation:

The general molecular formula of alkanes (saturated hydrocarbons) is:

CₙH₂ₙ₊₂

Where n = number of carbon atoms.

The general molecular formula of alkenes (unsaturated hydrocarbons) is:

CₙH₂ₙ

The general molecular formula of alkynes (unsaturated hydrocarbons) is:

CₙH₂ₙ₋₂

Now let us check the formula of given compounds

a)C₅H₁₂

n = 5

2n=10

2n+2=12

so this is an alkane, saturated hydrocarbon.

b)C₇H₁₆

n = 7

2n=14

2n+2=14

so this is an alkane, saturated hydrocarbon.

c)C₆H₁₄

n = 6

2n=12

2n+2=14

so this is an alkane, saturated hydrocarbon.

d) C₈H₁₆

n = 8

2n=16

2n+2=18

2n-2=14

so this is an alkyne, unsaturated hydrocarbon.

Delicious77 [7]4 years ago

5 0

(4) C8H14 is your answer. A saturated hydrocarbon means that they have no double or triple bonds. C8H14 is an alkyne, which is an unsaturated hydrocarbon.

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When a substance undergoes a change

Amiraneli [1.4K]

Answer:D

Explanation:Each time state transforms into a solid matter thus a physical property is the answer.BRAINLIEST PLEASE

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2 years ago

A 30-0 g sample of water at 280 K is mixed with 50.0 g of water at 330 K. How would you calculate the final temperature of the m

aliya0001 [1]

Answer:

311.25k

Explanation:

The question assumes heat is not lost to the surroundings, therefore

heat emitted from hotter sample ( $q_{\ lost}$ )= heat absorbed by the less hotter sample( $q_{\ gain}$ )

The relationship between heat (q), mass (m) and temperature (t) is $q = mc\Delta t$

where c is specific heat capacity, $\Delta t$ temperature change.

$\Delta t$ = $t_{\ final} - t_{\ initial}$

equating both heat emitted and absorb

$-q_{\ lost} = q_{\ gain}$

$-m_{1}(t_{\ final} - t_{\ 1initial})=m_{2}(t_{\ final} - t_{\ 2initial})$

where the values with subset 1 are the values of the hotter sample of water and the values with subset 2 are the values of the less hot sample of water.

C will cancel out since both are water and they have the same specific heat capacity.

so we have

$-m_{1}(t_{\ final} - t_{\ 1initial})=m_{2}(t_{\ final} - t_{\ 2initial})$

where m1 = 50g, t 1initial = 330, m2 = 30g, t2 initial = 280,t final (final temperature of the mixture) = ?

-50 * ( $t_{final}$ - 330) = 30 * ( $t_{final}$ - 280)

-50 $t_{final}$ + 16500 = 30 $t_{final}$ - 8400

80 $t_{final}$ = 16500+8400

80 $t_{final}$ = 24900

$t_{final}$ = 24900/80 = 311.25k

8 0

3 years ago

How many kilograms of dry air are in a room that measures 15.0 ft by 18.0 ft by 8.00 ft? Use the density of air of 1.168 g/L. Th

Nady [450]

Answer:

0.0481 kg.

Explanation:

First, we need to find the volume of the room.

15 x 18 x 8 = 1350

The volume of the room is 1350 ft³

Now, we convert feet to centimeters

1350 x 30.48 = 41,148

The volume is 41,148 cm³

1 cm³ = 1 mL

So we can say that the volume of the room is also 41,148 mL

Then, we convert milliliters to liters

41,148 ÷ 1,000 = 41.148

There are 41.148 liters of air in the room

We multiply the air's density with volume in liters

41.148 x 1.168 = 48.060864

There are 48.060864 grams of air in the room

Finally, convert grams to kilograms

48.060864 ÷ 1,000 = 0.048060864

0.048060864 kilograms of air are in the room.

4 0

3 years ago

0.513 mol Al2O3 = g Al2O3

Dovator [93]

Answer:

Molar mass (M) = mass(m) / number of moles (n)

To find the mass of Al2O3 first calculate it's molar mass

thus

M(Al2O3) = (27×2) + (16 × 3)

= 54 + 48

= 102g/mol

Mass of Al2O3 = molar mass × number of moles

= 102 × 0.513

= 52.326g of Al2O3

Hope this helps

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3 years ago

Class science A lunar eclipse occurs when

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Answer:

when the moon passes through earth's shadow

Explanation:

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3 years ago

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