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3 years ago

Which of the following is the closest star to our solar system

Physics

1 answer:

vivado [14]3 years ago

3 0

Answer:

Proxima Centauri, the closest star to our own, is still 40,208,000,000,000 km away.

Explanation:

Proxima Centauri, → 40,208,000,000,000 km

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A bird travels 1.70 x 10^4 km south then turns around and travels 6.00 x 10^2 north. He then turns around again immediately and

Citrus2011 [14]

The distance the bird flies is (17,000 + 600 + 14,400) = 32,000 km.

His average speed is (32,000 km)/(122 days) = 262.3 km/day.

The bird ends up (17,000 - 600 + 14,400) = 30,800 km north
from where he started.

His average velocity is (30,800 km)/(122 days) = 252.5 km/day north .

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4 years ago

Please help! Which statements correctly describe the effect of distance in determining the gravitational force and the electrica

Vera_Pavlovna [14]

There are six statements on the list.

The first 2 are true, and the last 2 are true.

The 2 in the middle aren't true. They are false.

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3 years ago

What is the average kinetic energy of helium atoms in a region of the solar corona where the temperature is 5.90 x 10^5 K?

OLEGan [10]

Answer: The average kinetic energy of helium atoms is $1.222\times 10^{-17}J$

Explanation:

To calculate the average kinetic energy of the atom, we use the equation:

$K=\frac{3}{2}kT$

where,

K = average kinetic energy = ?

k = Boltzmann constant = $1.3807\times 10^{-23}J/K$

T = temperature = $5.9\times 10^5K$

Putting values in above equation, we get:

$K=\frac{3}{2}\times 1.3807\times 10^{-23}J/K\times 5.9\times 10^5K\\\\K=1.222\times 10^{-17}J$

Hence, the average kinetic energy of helium atoms is $1.222\times 10^{-17}J$

4 0

3 years ago

A horizontal uniform bar of mass 2.7 kg and length 3.0 m is hung horizontally on two vertical strings. String 1 is attached to t

Jlenok [28]

Answer:

14.36 N

Explanation:

$T_{1}$ = Tension in string 1

$T_{2}$ = Tension in string 2

$m_b$ = mass of the bar = 2.7 kg

$W_b$ = weight of the bar

weight of the bar is given as

$W_b = m_{b} g = (2.7) (9.8) = 26.46$ N

$m_m$ = mass of the bar = 1.35 kg

$W_m$ = weight of the monkey

weight of the monkey is given as

$W_m = m_{m} g = (1.35) (9.8) = 13.23$ N

Using equilibrium of torque about left end

$W_{m} (AB) + W_{b} (AB) = T_{2} (AC)\\W_{m} (AB) + W_{b} (AB) = T_{2} (AD - CD)\\(13.23) (1.5) + (26.46)(1.5) = T_{2} (3 - 0.65)\\\\T_{2} = 25.33$ N

Using equilibrium of force in vertical direction

$T_{1} + T_{2} = W_{b} + W_{m}\\T_{1} + 25.33 = 26.46 + 13.23\\T_{1} = 14.36$ N

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3 years ago

Ken’s community is completely dependent on agriculture for their income. They cultivate and breed domestic species for their foo

Katena32 [7]

This is an agrarian society, taken to its extreme. These societies are largely dependent upon farming and related activities as a way of earning income, and also for using the farmed items as a way of supporting oneself as food and clothing.

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3 years ago

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