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3 years ago

Which of the following is the closest star to our solar system

Physics

1 answer:

vivado [14]3 years ago

3 0

Answer:

Proxima Centauri, the closest star to our own, is still 40,208,000,000,000 km away.

Explanation:

Proxima Centauri, → 40,208,000,000,000 km

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How to find time In flight

Romashka-Z-Leto [24]

To solve any problem in math or physics, you collect all the formulas,
laws, rules, and equations that you know about the subject, then, along
with the given information, use them to find the missing information.

So the answer to "how" really depends on what information you're given.

3 0

3 years ago

A tennis player practices against a wall, hitting a 0.1 kg ball towards the

pantera1 [17]

Answer: 80 Newton

Explanation:

Initial velocity of ball = +20 m/s.

Final velocity of ball = -20 m/s

Mass of ball = 0.1kg

Time taken = 0.05 seconds

Average force = (Change in momentum of moving ball / Time taken)

Since, change in momentum = Mass (final velocity - initial velocity)

Change in momentum =0.1 x (-20 - (+20))

= 0.1 x (-20-20)

= 0.1 x (-40)

= -4.0 kgm/s

Then, put -4.0 kgm/s in the equation of force when Average Force = (Change in momentum / Time taken)

= (-4.0kgm/s / 0.05 seconds)

= 80Newton (note that the negative sign does not reflect on the magnitude of force)

Thus, the average force exerted on the ball is 80N

3 0

3 years ago

Excellent human jumpers can leap straight up to a

Shkiper50 [21]

The speed that the person needs to leave the ground will be 4.32m/s

From the question given,

Height = 95cm

Since the person leave the ground v = 0m/s

acceleration due to gravity g = 9.8m/s²

Using the equation of motion

v² = u² + 2as

a = -g (upward motion)

s = h (distance changes to height)

The equation will become:

0² = u² - 2gh

0² = u² - 2(9.8)(0.95)

u² = 18.62

u = √18.62

u = 4.32

Hence the speed that the person needs to leave the ground will be 4.32m/s

Learn more here: brainly.com/question/20352766

8 0

2 years ago

A newly discovered planet has the same mass as the Earth, but a person standing on the surface of the planet experiences a force

Dafna11 [192]

This question deals with the acceleration due to gravity on the surface of the planet. The value of the acceleration due to gravity on the surface of two planets, that is Earth and on the surface of another planet are compared to find out the relation between the radii of both planets, provided their masses are the same.

The correct option for the radius of the new planet is "Option 3: Square Root of 3 R"

The value of the acceleration due to gravity on the surface of a planet is given by the following formula:

$g = \frac{GM}{R^2}$ ----------- eqn(1)

where,

g = acceleration due to gravity on Earth

G = Universal Gravitational Constant

M = mass of the Earth

R = Radius of the Earth

Now, the same formula for the acceleration due to gravity on the surface of the other planet can be written as follows:

$g' = \frac{GM'}{R'}\\\\$ ------------- eqn(2)

where,

g' = acceleration due to gravity on the new planet

G = Universal Gravitational Constant

M' = mass of the new planet

R' = Radius of the new planet

According to the given condition, the new planet has the same mass as the Earth's mass but the acceleration due to gravity on the surface of the new planet is one-third of the acceleration due to gravity on the surface of Earth.

$M'=M\\\\g'=\frac{1}{3}g$