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3 years ago

In a redox reaction, why does an element's oxidation number increase

1 answer:

5 0

If the element is oxidized, then it's oxidation number would increase.

Let's say we have the following reaction.
2H2O --> O2 + 2H2

To the left, the oxidation number of O is -2, as it is bonded to two H, which is always H+. To the right, we have O2, and all gases have a oxidation number of 0 (zero). We say that O has been oxidized.

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A block has a mass of 30g and dimensions of 1.5cm by 4.8cm by 2.3cm. Calculate the density (round to TWO sig figs).

adelina 88 [10]

Answer:

1.8g/cm³

Explanation:

Density is defined as the ratio of the mass of a substance and the space this subtance occupies. It is usually given in g/cm³.

The mass of the block is 30g.

The volume this mass occupies is 1.5cm × 4.8cm × 2.3cm = 16.56cm³.

The density is:

30g / 16.56cm³ =

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3 years ago

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Daniel [21]

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2 years ago

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a 0.258 g piece of potassium solid is placed inot water inside a coffee cup calorimeter resulting in a vigorous reaction. assume

kramer

Answer:

5 kJ/g

Explanation:

There are two energy flows in this reaction.

q₁ = heat from reaction

q₂ = heat to warm the solution

q₁ + q₂ = 0

m₁ΔH + m₂CΔT = 0

Data:

m₁ = 0.258 g

V₂ = 100 mL

C = 4.184 J°C⁻¹g⁻¹

T_i = 22 °C

T_f = 25.1 °C

Calculations

(a) Mass of solution

$\text{Mass} = \text{100 mL} \times \dfrac{\text{1.00 g}}{\text{1 mL}} = \text{100 g}$

(b) ΔT

ΔT = T_f - T_i = 25.1 °C - 22 °C = 3.1°C

(c) ΔH

$\begin{array}{ccccl}m_{1}\Delta H & +& m_{2}C \Delta T& = &0\\\text{0.258 g}\times \Delta H& + & \text{100 g} \times 4.184 \text{ J$^{\circ}$C$^{-1}$g$^{-1}$} \times 3.1 \, ^{\circ}\text{C} & = & 0\\0.258 \Delta H \text{ g} & + & \text{1300 J} & = & 0\\&&0.258 \Delta H \text{ g} & = & \text{-1300 J} & & \\& &\Delta H & = & \dfrac{\text{-1300 J}}{\text{0.258 g}}\\\\& & & = & \text{-5000 J/g}\\& & & = & \textbf{-5 kJ/g}\\\end{array}$

$\text{The reaction produces $\large \boxed{\textbf{5 kJ}}$ per gram of potassium.}$

Note: The answer can have only one significant figure because you measured the initial temperature of the water only to the nearest degree.

4 0

3 years ago