Which is the formula for dinitrogen pentoxide? A)N5O2 B)5N2O C) 2NO5 D) N2O5

Which are characteristics of photosynthesis? (Select all that apply.) Oxygen is provided to animals from this process. It takes

Liono4ka [1.6K]

Answer:

2 , 3 and 4

Explanation:

hope this helps you

8 0

2 years ago

In the reaction below, if a total of 10.0 g of zinc and hydrochloric acid react completely, what is the total mass of zinc chlor

Sloan [31]

Answer:

Not enough information to tell.

Explanation:

What is given?

Mass of Zn = 10.0 g,

Mass of HCl = 10.0 g,

Molar mass of Zn = 65.4 g/mol,

Molar mass of HCl = 36.4 g/mol,

Molar mass of ZnCl2 = 136.2 g/mol,

Molar mass of H2 = 2 g/mol.

Step-by-step solution:

First, let's convert 10.0 g of each reactant to moles using their respective molar mass:

$\begin{gathered} 10.0\text{ g Zn}\cdot\frac{1\text{ mol Zn}}{65.4\text{ g Zn}}=0.153\text{ moles Zn,} \\ \\ 10.0\text{ g HCl}\cdot\frac{1\text{ mol HCl}}{36.4\text{ g HCl}}=0.275\text{ moles HCl.} \end{gathered}$

Now, let's identify what is the limiting reactant. Let's see how many moles of ZnCl2 can be produced by 0.153 moles of Zn if 1 mol of Zn reacted produces 1 mol of ZnCl2, and how many moles of ZnCl2 can be produced by 0.275 moles of HCl if 2 moles of HCl reacted produces 1 mol of ZnCl2:

$\begin{gathered} 0.153\text{ moles Zn}\cdot\frac{1\text{ mol ZnCl}_2}{1\text{ mol Zn}}=0.153\text{ moles ZnCl}_2, \\ \\ 0.275\text{ moles HCl}\cdot\frac{1\text{ mol ZnCl}_2}{2\text{ moles HCl}}=0.138\text{ moles ZnCl}_2. \end{gathered}$

You can realize that the limiting reactant, in this case, is HCl because is the first reactant consumed first and this reactant 'impose' the limit to produce the products.

So now, let's find how many moles of H2 are being produced by 0.275 moles of HCl if 2 moles of HCl reacted produces 1 mol of H2:

$0.275\text{ moles HCl}\cdot\frac{1\text{ mol H}_2}{2\text{ moles HCl}}=0.138\text{ moles H}_2.$

The final step is to convert each number of moles of each product to grams using their respective molar mass, as follows:

$\begin{gathered} 0.138\text{ moles ZnCl}_2\cdot\frac{136.2\text{ g ZnCl}_2}{1\text{ mol ZnCl}_2}=18.8\text{ g ZnCl}_2, \\ \\ 0.138\text{ moles H}_2\cdot\frac{2\text{ g H}_2}{1\text{ mol H}_2}=0.276\text{ g H}_2. \end{gathered}$

We're producing 18.8 g of zinc chloride (ZnCl2), and 0.276 g of hydrogen (H2), so based on this logic the answer would be not enough information to tell.

5 0

1 year ago

I NEED HELP ASAP IM ON AN EXAM ONLY CORRECT ANSWERS WILL MARK BRAINLIST

irina [24]

ANSWER:

Applied research, because it is solving a problem.

EXPLANATION:

Pure research refers to the systematic study of life aimed at fuller knowledge or a deeper understanding of the theoretical aspects of a phenomenon. On the other hand, applied research is a systematic, empirical study undertaken to generate knowledge for problem-solving in a very broad sense.

6 0

3 years ago

g 2BrO3- + 5SnO22-+ H2O5SnO32- + Br2+ 2OH- In the above reaction, the oxidation state of tin changes from to . How many electron

Archy [21]

Answer:

In the above reaction, the oxidation state of tin changes from 2+ to 4+.

10 moles of electrons are transferred in the reaction

Explanation:

Redox reaction is:

2BrO₃⁻ + 5SnO₂²⁻ + H2O ⇄ 5SnO₃²⁻ + Br₂ + 2OH⁻

SnO₂²⁻ → SnO₃²⁻

Tin changes the oxidation state from +2 to +4. It has increased it so this is the oxidation from the redox (it released 2 e⁻). We are in basic medium, so we add water in the side of the reaction where we have the highest amount of oxygen. We have 2 O on left side and 3 O on right side so we add 1 water on the right and we complete with OH⁻ in the opposite side to balance the H.

SnO₂²⁻ + 2OH⁻ → SnO₃²⁻ + 2e⁻ + H₂O Oxidation

BrO₃⁻ → Br₂

First of all, we have unbalance the bromine, so we add 2 on the BrO₃⁻. We have 6 O in left side and there are no O on the right, so we add 6 H₂O on the left. To balance the H, we must complete with 12OH⁻. Bromate reduces to bromine at ground state, so it gained 5e⁻. We have 2 atoms of Br, so finally it gaines 10 e⁻.

6H₂O + 10 e⁻ + 2BrO₃⁻ → Br₂ + 12OH⁻ Reduction

In order to balance the main reaction and balance the electrons we multiply (x5) the oxidation and (x1) the reduciton

(SnO₂²⁻ + 2OH⁻ → SnO₃²⁻ + 2e⁻ + H₂O) . 5

(6H₂O + 10 e⁻ + 2BrO₃⁻ → Br₂ + 12OH⁻) . 1

5SnO₂²⁻ + 10OH⁻ + 6H₂O + 10 e⁻ + 2BrO₃⁻ → Br₂ + 12OH⁻ + 5SnO₃²⁻ + 10e⁻ + 5H₂O

We can cancel the e⁻ and we substract:

12OH⁻ - 10OH⁻ = 2OH⁻ (on the right side)

6H₂O - 5H₂O = H₂O (on the left side)

2BrO₃⁻ + 5SnO₂²⁻ + H2O ⇄ 5SnO₃²⁻ + Br₂ + 2OH⁻

6 0

4 years ago

How do we know whether an element is a metal or a non metal from its atomic number? 1;f the valence electron number is either 1,

marysya [2.9K]

Explanation:

The valence number represents the number of electrons in the outermost shell of the atom. Interestingly, in a group 1 -8 periodic tale, the number represents the valence electrons.

Thus means that group 3 electrons have a valency of 3; that is all group 3 elements have 3 electrons in their outermost shell.

Metals easily lose electrons rather than gain electrons while non metals gain electrons.

In the periodic table; groups 1, 2, 3 represents metals and from group 4 upwards we have non metals.

Going through the options now, the correct option is;

3:if the valence electron number is either 1,2 or 3 then it is a Metal and if the valence electron number is either 4,5 or 6 then it is a Non Metal

Group 7 elements ( Valency of 7) are also non metals.

8 0

3 years ago