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3 years ago

How do different factors affect solubility? Check all of the boxes that apply.

Chemistry

1 answer:

Anni [7]3 years ago

3 0

Answer:

Dear, your answer is

solubility is affected by current concentration, mechanical disturbance, temperature and pressure. So the answers are:

- Increasing temperature decreases the solubility of gases.

- Stirring increases the solubility of solids.

- Increasing pressure increases the solubility of gases.

- Decreasing the amount of solvent decreases the solubility of solids, liquids, and gases.

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Find an expression for the change in entropy when two blocks of the same substance of equal mass, one at the temperature Th and

Gre4nikov [31]

Explanation:

Relation between entropy change and specific heat is as follows.

$\Delta S = C_{p} log (\frac{T_{2}}{T_{1}})$

The given data is as follows.

mass = 500 g, $C_{p}$ = 24.4 J/mol K

$T_{h}$ = 500 K, $T_{c}$ = 250 K

Mass number of copper = 63.54 g /mol

Number of moles = $\frac{mass}{/text{\molar mass}}$

= $\frac{500}{63.54}$

= 7.86 moles

Now, equating the entropy change for both the substances as follows.

$7.86 \times 24.4 \times [T_{f} - 250]$ = $7.86 \times 24.4 \times [500 -T_{f}]$

$T_{f} - 250 = 500 - T_{f}$

$2T_{f}$ = 750

So, $T_{f}$ = $375^{o}C$

For the metal block A, change in entropy is as follows.

$\Delta S = C_{p} log (\frac{T_{2}}{T_{1}})$

= $24.4 log [\frac{375}{500}]$

= -3.04 J/ K mol

For the block B, change in entropy is as follows.

$\Delta S = C_{p} log (\frac{T_{2}}{T_{1}})$

= $24.4 log [\frac{375}{250}]$

= 4.296 J/Kmol

And, total entropy change will be as follows.

= 4.296 + (-3.04)

= 1.256 J/Kmol

Thus, we can conclude that change in entropy of block A is -3.04 J/ K mol and change in entropy of block B is 4.296 J/Kmol.

8 0

3 years ago

I don't know any things

d1i1m1o1n [39]

A cell is made of molecules and a molecule is made of atoms. That's the simplest way of putting it. More complicated is that a cell is made up of macromolecules, such as proteins, lipids, etc. A molecule is a particular configuration of atoms.

4 0

4 years ago

Read 2 more answers

At what temp will a gas be at if you allow it to expand from an original 456 mL to 65°C to 3.4 L

alexira [117]

We use the gas law named Charle's law for the calculation of the second temperature. The law states that,
V₁T₂ = V₂T₁
Substituting the known values,
(0.456 L)(65 + 273.15) = (3.4 L)(T₁)
T₁ = 45.33 K

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3 years ago

Read 2 more answers

Solve each of the following problems using one or more conver-sion factors:a. A container holds 0.500 qt of liquid. How many mil

svetoff [14.1K]

Answer:

a. 473mL.

b. 79.38kg

c. 24.47lb of fat

d. 42.5g of N.

Explanation:

a. A qt is equal to 946mL. 0.500qt are:

0.500qt * (946mL / 1qt) = 473mL

b. 1lb is equal to 0.4536kg, 175lb are:

175lb *(0.4536kg / 1lb) = 79.38kg

c. The fat in kg of the athlete is:

74kg * 15% = 11.1kg of fat. In pounds:

11.1kg * (1lb / 0.4536kg) = 24.47lb of fat

d. The mass of nitrogen in the fertilizer is:

10.0oz * 15% = 1.5oz of N

1 oz is equal to 28.35g. 1.5oz are:

1.5oz * (28.35g / 1oz) = 42.5g of N

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3 years ago

Hydrochloric acid is widely used as a laboratory reagent in refining ore for the production of tin and tantalum, and as a cataly

Lyrx [107]

<u>Answer: </u>0.0285 moles of HCl is present in given amount of solution.

<u>Explanation:</u>

Molarity is defined as the amount of solute expressed in the number of moles present per liter of solution. The units of molarity are mol/L. The formula used to calculate molarity:

$\text{Molarity of solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (mL)}}$ .....(1)

Given values:

Molarity of HCl = 0.453 M

Volume of solution = 62.85 mL

Putting values in equation 1, we get:

$0.453mol/L=\frac{\text{Moles of HCl}\times 1000}{62.85}\\\\\text{Moles of HCl}=\frac{0.453\times 62.85}{1000}=0.0285moles$

Hence, 0.0285 moles of HCl is present in given amount of solution.

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3 years ago