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salantis [7]
2 years ago
10

If there is only one type of cation that can be formed from an element, what do we do with its name?

Chemistry
1 answer:
KatRina [158]2 years ago
6 0

Answer:

Magnesium, Mgstart text, M, g, end text, is a group 2 element that will form 2+ cations. Because it usually forms cations of only one type, we don't need to specify its charge. We can simply refer to the cation in the ionic compound as magnesium. ... Therefore, the name for the compound is magnesium phosphide.

Explanation:

(this may or not be correct)

-also i finished that drawing you wanted :p-

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Is a push or a pull.<br><br><br> A.FORCE<br> B.MASS <br><br> ???
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A.Force because your adding pressure to what you are pushing or pulling.
4 0
3 years ago
After standardizing a NaOH solution, you use it to titrate an HCl solution known to have a concentration of 0.203 M. You perform
jek_recluse [69]

Answer:

0.203 is the mean of the concentration of the HCl solution

Explanation:

You have 5 concentrations. The most appropiate result is the mean of those results. The mean is a statistical defined as the sum of each result divided by the total amount of results. For the results of the problem, the mean is:

0.210 + 0.204 + 0.201 + 0.202 + 0.197 = 1.014 / 5 =

<h3>0.203 is the mean of the concentration of the HCl solution</h3>
8 0
2 years ago
Identify the number of protons and electrons
vredina [299]
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6 0
2 years ago
A 400 ml sample of gas is heated from -20 c to 60
Viktor [21]
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p1=50
p2=225
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v2=?
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6 0
3 years ago
Read 2 more answers
If you initially have a volume of 4 L and a temperature of 300K. Then you decreased the volume to 2 L, what is the new temperatu
ASHA 777 [7]

Answer:

T₂ = 150 K

Explanation:

Given data:

Initial volume = 4 L

Initial temperature = 300 K

Final volume = 2 L

Final temperature = ?

Solution:

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

T₂ = T₁V₂/V₁  

T₂ = 300 K × 2L / 4 L

T₂ = 600 L.K / 4 L

T₂ = 150 K

3 0
2 years ago
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