Question 7 of 10
1 answer:
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Answer:
A. True
Explanation:
When a stone is thrown straight-up, it has an initial velocity which decreases gradually as the stone move to maximum height due to constant acceleration due to gravity acting downward on the stone, at the maximum height the final velocity of the stone is zero. As the stone descends the velocity starts to increase and becomes maximum before it hits the ground.
Height of the motion is given by;
g is acceleration due to gravity which is constant
H is height traveled
u is the speed of throw, which determines the value of height traveled.
Therefore, when the stone is caught at the same height from which it was thrown in the absence of air resistance, the speed of the stone when thrown will be equal to the speed when caught.
Answer:
f = 692 N
Explanation:
given data:
f =800N
a =1.2 m s^{2}
m= 90 kg
from newton's second law
net force
therefore we have from above equation
ma =F - f
putting all value to get force of friction
1.2*90 = 800 - f
f = 692 N
Answer:
The force, exerted by Big Ben on the Empire State Building is 2.66972 × 10⁻⁷ N
Explanation:
The question relates to the force of gravity experienced between two bodies
The given parameters are;
The mass of Big Ben, M₁ = 1 × 10⁸ kg
The mass of the Empire State Building, M₂ = 1 × 10⁹ kg
The distance between the two Big Ben and the Empire State Building, r = 5,000,000 meters
By Newton's Law of gravitation, we have;
Where;
F = The force exerted by Big Ben on the Empire State Building and vice versa
G = The universal gravitational constant = 6.67430 × 10⁻¹¹ N·m²/kg²
M₁, M₂, and r are the given parameters
By plugging in the values of the parameters and the constant into the equation for Newton's Law of gravitation, we have;
The force, 'F', exerted by Big Ben on the Empire State Building is F = 2.66972 × 10⁻⁷ N.