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ad-work [718]
3 years ago
6

The following currents are measured in the same direction in a three-branch parallel circuit: 250 mA, 300 mA, and 800 mA. What i

s the value of the current into the junction of these three branches?
Physics
1 answer:
Ksju [112]3 years ago
5 0

The current in the junction is 1350 mA or 1.350 A.

Explanation:

As per Kirchoff's first law, the algebraic sum of current meeting at any junction should be equal to the algebraic sum of current leaving the junction. As in the present case, three parallel branch circuit is given the current in 250 mA, 300 mA and 800 mA, respectively, the sum of these three current will be equal to the current in the junction.

So,

I₁+I₂+I₃ = I₄

So I₁,I₂ and I₃ are the current passed in the three parallel branches and I₄ is the current in the junction.

250 + 300 + 800 = 1350 mA

So the current in the junction is 1350 mA or 1.350 A.

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an object near the surface of a planet falls 54m in 3s. what is the acceleration due to gravity on that planet
Harman [31]

Answer:

12s

Explanation:

7 0
3 years ago
A 4.0 Ohms resistor, an 8.0 Ohms resistor, and a 12.0 Ohms resistor are connected in series with a 24.0 V battery. Calculate the
Flura [38]

Answer:

RESISTANCE=(4+8+12)Ohms

=24 ohms

V=IR

24= I ×24

I= 24/24

I= 1 A

CURRENT IS 1 A

8 0
3 years ago
Read 2 more answers
One end of a string 4.32 m long is moved up and down with simple harmonic motion at a frequency of 75 Hz . The waves reach the o
max2010maxim [7]

To solve this problem, we will apply the concepts related to the kinematic equations of linear motion, which define speed as the distance traveled per unit of time. Subsequently, the wavelength is defined as the speed of a body at the rate of change of its frequency. Our values are given as,

\text{Length of the string} = L = 4.32 m

\text{Frequency of the wave} = f = 75 Hz

\text{Time taken to reach the other end} = t = 0.5 s

Velocity of the wave,

V = \frac{L}{t}

V = \frac{4.32 m}{0.5s}

V = 8.64m/s

Wavelength of the wave,

\lambda = \frac{V}{f}

\lambda = \frac{8.64m/s}{75Hz}

\lambda = 0.1152m

\lambda = 11.52cm

Therefore the wavelength of the waves on the string is 11.53 cm

4 0
3 years ago
Read 2 more answers
A wedge shaped air film is made between two sheets of glass using a spacer at one end of the glass sheets. If light of wavelengt
pychu [463]

Answer:

1178 nm

Explanation:

We are given that

Wavelength of light=\lambda=589nm=589\times 10^{-9} m

1nm=10^{-9} m

We have to find the thickness of spacer if five dark fringes are observed between the edges of the glass.

Suppose that first dark fringe and fifth dark fringe near spacer, then the path length of light is 4 times the wavelength of light.

The light passes through air film is two times  then the change in air film thickness  from one edge to other is two times the wavelength of light.

Change in air film thickness  from one edge to other edge  is same as the thickness of spacer.

Therefore, thickness of spacer=2\lambda

Thickness of spacer=2\times 589\times 10^{-9}m

Thickness of spacer=1178 nm

Hence, the thickness of spacer=1178 nm

8 0
3 years ago
"Suppose you tie a rock to the end of a 0.96 m long string and spin it in a horizontal circle with a constant angular velocity o
Ber [7]

Answer:

The mass of the rock is  m = 2.46406 \ kg

Explanation:

From the question we are told that

   The length of the string is  l  = 0.96 \ m

    The angular velocity is  w =  20.25 \ rad/s

     The tension on the string is T  = 970 \ N

Generally the centripetal force acting on the rock is mathematically evaluated as

       T = mlw^2

making m the subject of the formula

      m = \frac{T}{w^2 * l}

substituting values

     m = \frac{970}{(20.25^2) * (0.96)}

     m = 2.46406 \ kg

       

8 0
3 years ago
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