Answer
From
V=Distance/time
The distance round a circular path or Object is 2πr
so
v=2πr/T
Making T(period) subject
T=2πr/v
where v is the linear velocity.
We don't have the velocity but we can get it.
The Moon and Earth exert gravitational force on each other and the Moon is kept in Orbit by Centripetal force.
Since the Moon doesn't fly out of Orbit... it must mean that the Gravitational force being exerted on it by the Earth is equal to its centripetal Force.
Equating Both (Fg=Fc)
Fg=GMm/R²
Fc=mv²/r
GMm/R² = mv²/R
Canceling out "m" and "r" on both sides
we're left with
V²=GM/R
V=√GM/R
Where M= Mass of Earth (5.98x10^24)
R=Distance between the center of earth and the Moon
G= Gravitational Constant(Value 6.67x10^-11)
V=√6.67x10^-11 x 5.98x10^24/(3.82x10^8)
V=1021.84meters per second.
Now
T=2πr/v
=2π x 3.82x10^8 / 1021.84
T=2.35x10^6seconds
Converting to days by dividing by(24 x 3600)
You have
T=27.2days approx.
✅✅✅
No it can’t. The result of interaction is force and for interaction, we
need two. I am hoping that this answer has satisfied your query and it
will be able to help you in your endeavor, and if you would like, feel free to
ask another question.
Answer:
they are comparing themselves to other ppl
Answer:
88 m/s
Explanation:
To solve the problem, we can use the following SUVAT equation:
where
v is the final velocity
u is the initial velocity
a is the acceleration
d is the distance covered
For the car in this problem, we have
d = 484 m is the stopping distance
v = 0 is the final velocity
is the acceleration
Solving for u, we find the initial velocity:
Answer:
The light scatters in all directions.
