Answer:
both
Explanation:
and I'm serious he is literally both
Answer:
A=0.199
Explanation:
We are given that
Mass of spring=m=450 g=
Where 1 kg=1000 g
Frequency of oscillation=
Total energy of the oscillation=0.51 J
We have to find the amplitude of oscillations.
Energy of oscillator=
Where =Angular frequency
A=Amplitude
Using the formula
Hence, the amplitude of oscillation=A=0.199
a increase in the velocity by 8ms increase every second the math is you take the base velocity usually 0 but in this case 25 and subtract that by the top velocity which is 49 and then divide by the time of increase which is 3 so your answer is 8ms increase per second
Answer:
x = 5.29 m
Explanation:
given,
weight of stretch = 37 N
left-hand spring constant (k₁)= 2.7 N/cm
right hand spring constant(k₂)= 4.3 N/ cm
spring are connected in parallel
F = F₁ + F₂
F = k₁x + k₂x
F = (k₁+ k₂)x
37= (4.3+ 2.7)x
7 x = 37
x = 5.29 m
a). Frequency = (4,000 rev/minute)·(1 minute/60 sec) = <em>66 and 2/3 rev/sec</em>
b). Period = 1 / frequency
Period = 1 / (66-2/3 rev/sec)
Period = 1/66-2/3 sec/rev
<em>Period = 0.015 sec/rev </em>