The person's horizontal position is given by
![x=v_0\cos40^\circ t](https://tex.z-dn.net/?f=x%3Dv_0%5Ccos40%5E%5Ccirc%20t)
and the time it takes for him to travel 56.6 m is
![56.6\,\mathrm m=\left(24.0\,\dfrac{\mathrm m}{\mathrm s}\right)\cos40^\circ t\implies t=3.08\,\mathrm s](https://tex.z-dn.net/?f=56.6%5C%2C%5Cmathrm%20m%3D%5Cleft%2824.0%5C%2C%5Cdfrac%7B%5Cmathrm%20m%7D%7B%5Cmathrm%20s%7D%5Cright%29%5Ccos40%5E%5Ccirc%20t%5Cimplies%20t%3D3.08%5C%2C%5Cmathrm%20s)
so your first computed time is the correct one.
The question requires a bit of careful reading, and I think there may be a mistake in the problem. The person's vertical velocity
at time
is
![v_y=v_{0y}-gt](https://tex.z-dn.net/?f=v_y%3Dv_%7B0y%7D-gt)
which tells us that he would reach the ground at about
. In this time, he would have traveled
![x=v_{0x}(3.15\,\mathrm s)=57.9\,\mathrm m](https://tex.z-dn.net/?f=x%3Dv_%7B0x%7D%283.15%5C%2C%5Cmathrm%20s%29%3D57.9%5C%2C%5Cmathrm%20m)
But we're told that he is caught by a net at 56.6 m, which would mean that the net cannot have been placed at the same height from which he was launched. However, it's possible that the moment at which he was launched doesn't refer to the moment the cannon went off, but rather the moment at which the person left the muzzle of the cannon a fraction of a second after the cannon was set off. After this time, the person's initial vertical velocity
would have been a bit smaller than
.
Answer:
MOMENTUM
Explanation:
another way of saying getting the smallest force possible is the word " MOMENTUM".
momentum is the ability to keep maintaining,incresing or itself developing to move at constant speed or to increase the speed.
A. a bicycle chain is an example of a compound machine
Force = Mass * Acceleration therefore the red ball with the higher mass will have more force and greater acceleration
Explanation:
We'll call the radius r and the diameter d:
We also assume that the riders are at a distance r = d/2 = 7m from the center of the wheel.
The period of the wheel is 24s. The tangent velocity of the wheel (and the riders) will be: (2pi/T)*r = 0.8 m/s (circa).
It means that in 3 minutes (180 seconds) they'll run 0.8 m/s * 180s = 144m.
Hopefully I understood the question. If yes, that's the answer.