Explanation:
here u = 50m/s
v = 60m/s
t = 58 s
then a = (60-50)/58 m/s2
= 0.17m/s2
now s= ut+1/2at2
so , 50×58+0.5×0.17×(58)^2 m
= 3185.94 m
= 3.18 km
Answer:3.54ohms
Explanation: connection in parallel
1/Rt= 1/R1+1/R2+1/R3
1/Rt= 1/16+1/13+1/7
1/Rt= 91+112+208/1456
1/Rt= 411/1456
411Rt= 1456
Rt= 1456/411
Rt= 3.54ohms
Answer:
2 m
Explanation:
The displacement of any body is the shortest distance in an object's path between its initial and final point.
The ball would travel 3 m from the point of throwing then fall down 5 m to the ground. The total distance traveled is 7 m.
The displacement of the ball will be the distance from the point of throwing to the ground i.e., 2 m as it is the shortest distance between the initial and final point of the ball's journey.
I suppose that you wanted write "uncharged". The particles without electrical charge present in the nucleus are called neutrons.
Answer:
Explanation:
a ) Slit separation d = .1 x 10⁻³ m
Screen distance D = 4 m
wave length of light λ = 650 x 10⁻⁹ m
Width of central fringe = λ D / d
= 
= 26 mm
b ) Distance between 1 st and 2 nd bright fringe will be equal to width of dark fringe which will also be equal to 26 mm
c ) Angular separation between the central maximum and 1 st order maximum will be equal to angular width of fringe which is equal to
λ / d
= 
= 6.5 x 10⁻³ radian.
