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yanalaym [24]
2 years ago
7

The eyepiece of a compound microscope has a focal length of 2.50 cm and the objective has a focal length of 1.60 cm. The two len

ses are separated by 15.0 cm. The microscope is used by a person with normal eyes (near point at 25 cm). What is the angular magnification of the microscope
Physics
1 answer:
larisa [96]2 years ago
4 0

The angular magnification of the microscope is 78.125.

<h3>What is angular magnification?</h3>

the ratio of the angle at the eye that an optical instrument's image occupies to the angle at the eye that an object occupies while not being viewed through an optical instrument is called as angular magnification.

Thus we can calculate it as:

  • focal length of objective lens, fo = 1.6 cm
  • focal length of the eyepiece, fe = 2.5 cm
  • Distance between the lenses, L = 15 cm
  • Least distance of distinct vision for normal eye, d = 25 cm

The formula for the magnification of the compound microscope is given by

M = - \frac{(L-f{e} )d}{fa fe}

M = - \frac{(15-2.5 )25}{(1.6) 2.5}

M = - 78.125

Thus, the magnification of the compound microscope is 78.125.

Learn more about angular magnification here:

brainly.com/question/17327671

#SPJ4

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3 years ago
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