Answer: Molarity of the solution is 
and water is the solvent.
Explanation:
Given: Mass of solute = 26.8 g
Volume = 4.00 L
Now, moles of copper (II) chloride (molar mass = 134.45 g/mol) are calculated as follows.
Molarity is the number of moles of a substance divided by volume of solution in liter.
Therefore, molarity of given solution is calculated as follows.
Solvent is defined as a component which is present in higher amount in a solution. Generally, a solvent is present in liquid state but it can also be a solid or gas.
In the given solution, copper (II) chloride is dissolved in water so copper (II) chloride is the solute and water is the solvent.
Thus, we can conclude that molarity of the solution is and water is the solvent.
Answer:
The ice chunk will take 2.47 seconds to hit the water.
Explanation:
Height from which ice chunk fell = h = 30.0 m
Initial velocity of the ice chunk = u = 0 m/s
Time taken by ice chunk to cover 30.0 m of height = t
Acceleration due to gravity = g 
Using second equation of motion ;
The ice chunk will take 2.47 seconds to hit the water.
Answer:
Explanation:
The combustion reaction of Octane is:
To calculate the mass of CO₂ and H₂O produced, we need to know the mass of octane combusted.
We calculate the mass of Octane from the given volume and density, using the following <em>conversion factors</em>:
Now we<u> convert 1.24 gallons to mL</u>:
- 1.24 gallon *
4693.4 mL
We <u>calculate the mass of Octane</u>:
- 4693.4 mL * 0.703 g/mL = 3.30 g Octane
Now we use the <em>stoichiometric ratios</em> and <em>molecular weights</em> to <u>calculate the mass of CO₂ and H₂O</u>:
- CO₂ ⇒ 3.30 g Octane ÷ 114g/mol *
* 44 g/mol = 10.19 g CO₂
- H₂O ⇒ 3.30 g Octane ÷ 114g/mol *
* 18 g/mol = 4.69 g H₂O
Answer:
Every 15 degrees is an hour
Explanation:
What is the time difference in mean solar time between 30° N 75° W and 30° N 90° W?
I believe the balanced chemical equation is:
C6H12O6 (aq) + 6O2(g)
------> 6CO2(g) + 6H2O(l)
First calculate the
moles of CO2 produced:
moles CO2 = 25.5 g
C6H12O6 * (1 mol C6H12O6 / 180.15 g) * (6 mol CO2 / 1 mol C6H12O6)
moles CO2 = 0.8493 mol
Using PV = nRT from
the ideal gas law:
<span>V = nRT / P</span>
V = 0.8493 mol *
0.08205746 L atm / mol K * (37 + 273.15 K) / 0.970 atm
<span>V = 22.28 L</span>
