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enot [183]
3 years ago
11

Write a Formula Compound Name: Strontium Sulfate

Chemistry
2 answers:
Aneli [31]3 years ago
8 0
SrSO4 is the formula
Neporo4naja [7]3 years ago
4 0

Answer:

it's SrSO4

Explanation:

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A balloon is inflated with 1.25 L of helium at a temperature of 298K. What is
Monica [59]

Answer:

What is

the volume of the balloon when the temperature is 310K?

7 0
3 years ago
What is 4/5-1/2-1/5​
zimovet [89]

Answer:

\frac{1}{10}

Explanation:

First write all numerators above the common denominator

4/5 - 1/2 - 1/2=

\frac{4-1}{5}- 1/2

Subtract the numbers

\frac{4-1}{5}- 1/2 =

\frac{3}{5} - \frac{1}{2}

Write all numerators above the least common denominator 10

\frac{3}{5} - \frac{1}{2} =

\frac{6-5}{10}

Subtract the numbers and you got your answer :)

8 0
3 years ago
Read 2 more answers
The specific silver is How many joules of energy are needed to warm 4.37 g of silver from 25.0 degrees * C to 27.5 degrees * C ?
Alexxandr [17]

0.24J/g*degC * 4.37g * 2.5degC = 2.622J

The 2.5 degC is the difference between 25 and 27.5 deg C.

6 0
4 years ago
The N H 2 group makes the molecule an amine. Like alcohols, amines can participate in hydrogen bonding. If the drawn molecule en
lesantik [10]

Answer:

a hydrogen bond between the hydrogen of water and the nitrogen of the amine

a hydrogen bond between the oxygen of water and a hydrogen from the -NH2 group

Explanation:

A hydrogen bond is formed between molecules in which hydrogen is bonded to a highly electronegative element.

In amines, hydrogen is bonded to nitrogen while in water, hydrogen is bonded to oxygen. Both are highly electronegative elements hence hydrogen bonding is possible between amines and water.

This hydrogen bond may involve;

The hydrogen of water and the nitrogen of the amine

Or

The oxygen of water and a hydrogen from the -NH2 group

7 0
3 years ago
When (R)-6-bromo-2,6-dimethylnonane is dissolved in CH3OH, nucleophilic substitution yields an optically inactive solution. When
3241004551 [841]

Answer:

See explanation

Explanation:

The nucleophile here is CH3OH. We know that CH3OH is a good nucleophile that promotes SN2 reanction. However, (R)-6-bromo-2,6-dimethylnonane is a tertiary alkyl halide so the reaction proceeds by SN1 mechanism. This means that a racemic mixture is obtained at the end of the reaction because the attack occurs at the stereogenic carbon atom (6R) hence the product is optically inactive.

On the other hand, when (5R)-2-bromo-2,5-dimethylnonane is reacted with CH3OH, an optically active product is obtained because; though a tertiary alkyl halide and reaction occurs by SN1 mechanism, the attack does not occur at the stereogenic carbon atom (5R). Therefore, an optically active product is obtained in this case.

7 0
3 years ago
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